Android执行POST请求

String uriAPI = "http://192.168.1.100:8080/test/test.jsp"; //这是我测试的本地,大家可以随意改
/*建立HTTPost对象*/
HttpPost httpRequest = new HttpPost(uriAPI);
/*
* NameValuePair实现请求参数的封装
*/
List <NameValuePair> params = new ArrayList <NameValuePair>();
params.add(new BasicNameValuePair("u", "沈大海"));
params.add(new BasicNameValuePair("p", "123"));
try
{
/* 添加请求参数到请求对象*/
httpRequest.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));
/*发送请求并等待响应*/
HttpResponse httpResponse = new DefaultHttpClient().execute(httpRequest);
/*若状态码为200 ok*/
if(httpResponse.getStatusLine().getStatusCode() == 200)
{
/*读返回数据*/
String strResult = EntityUtils.toString(httpResponse.getEntity());
mTextView1.setText(strResult);
}
else
{
mTextView1.setText("Error Response: "+httpResponse.getStatusLine().toString());
}
}
catch (ClientProtocolException e)
{
mTextView1.setText(e.getMessage().toString());
e.printStackTrace();
}
catch (IOException e)
{
mTextView1.setText(e.getMessage().toString());
e.printStackTrace();
}
catch (Exception e)
{
mTextView1.setText(e.getMessage().toString());
e.printStackTrace();
}
////大家能根据这个代码实现个android用户登陆吗?

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