Permutations

Permutations.go

回溯算法需要注意的是，填充结果的时候，需要copy一个slicefuncpermute(nums[]int)[][]int{varret[][]intl:=len(nums)ifl==0{returnret}helper(nums,0,l-1,&ret)returnret}funchelper(nums[]int,begin,endint,ret*[][]int){ifbegin==end{t:=
AnakinSun·2019-03-22 13:52

【转】使用backtrack解决Subsets, Permutations, Combination Sum, Palindrome Partioning的通用方法

出处：AgeneralapproachtobacktrackingquestionsinJava(Subsets,Permutations,CombinationSum,PalindromePartioning
JackComeOn·2019-02-28 16:51

Java实现n位数字的全排列

java代码如下：publicclassTest{staticintk=0;publicstaticvoidmain(String[]args){inta[]={1,2,3,4,5};permutations
gavenyeah·2019-02-18 15:36

Permutations

Givenacollectionofdistinctintegers,returnallpossiblepermutations.classSolution(object):defpermute(self,nums):""":typenums:List[int]:rtype:List[List[int]]"""return[[n]+pfori,ninenumerate(nums)forpinsel
云端漫步_b5aa·2019-02-14 23:54

Permutations

每个元素无重复无难度，DFSclassSolution(object):defpermute(self,nums):""":typenums:List[int]:rtype:List[List[int]]"""self.res=[]defdfs(nums,tmp):iflen(nums)==len(tmp):self.res.append(tmp[:])forminnums:ifmintmp:co
Neekity·2018-12-08 08:29

打印一个字符串的全部排列

08;importjava.util.HashSet;/****打印一个字符串的全部排列*打印一个字符串的全部排列，要求不要出现重复的排列**/publicclassCode_04_Print_All_Permutations
hasp_Jason·2018-10-09 13:28

046 Permutations

Givenacollectionofdistinctintegers,returnallpossiblepermutations.Example：Input:[1,2,3]Output:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]解释下题目：输出全排列喽1.递归调用呗实际耗时：3mspublicList>permute(int[]nums){L
烟雨醉尘缘·2018-10-03 22:52

Valid Permutations for DI Sequence

一、题目描述WearegivenS,alengthnstringofcharactersfromtheset{'D','I'}.(Theselettersstandfor“decreasing”and“increasing”.)AvalidpermutationisapermutationP[0],P[1],...,P[n]ofintegers{0,1,...,n},suchthatforalli
AzureoSky·2018-09-16 14:08

Permutations + 47. Permutations II

原题：47.PermutationsII46.Permutations初级版：46.Givenacollectionofdistinctintegers,returnallpossiblepermutations
默写年华Antifragile·2018-09-03 21:47

Permutations II

文章作者：Tyan博客：noahsnail.com|CSDN|1.DescriptionPermutationsII2.SolutionVersion1classSolution{public:vector>permuteUnique(vector&nums){vector>result;build(result,nums,0);returnresult;}private:voidbuild(ve
SnailTyan·2018-09-01 21:22

python技巧分享（十四）

/usr/bin/envpython#coding=utf8importitertoolsforpinitertools.permutations('ABC',2):printp'''('A','B')
songleo·2018-08-16 10:37

[Leetcode][深度优先/回溯法/DFS]相关题目汇总/分析/总结

Permutations/全排列求一组不重复的数的全排列PermutationsII/全排列II求一组数的全排列（有重复数字），返回不重复的全排列G
Rude3Knife·2018-08-15 14:21

【LeetCode】46. 全排列 结题报告 (C++)

原题地址：https://leetcode-cn.com/problems/permutations/description/题目描述：给定一个没有重复数字的序列，返回其所有可能的全排列。
暮雨凉初透·2018-07-30 10:30

LeetCode-046 Permutations

DescriptionGivenacollectionofdistinctintegers,returnallpossiblepermutations.ExampleInput:[1,2,3]Output:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]Analyse对给定的数列做个全排列，貌似这道题没有检查顺序，这时候就能偷个懒，用我们在031写
Yjl_Richard·2018-06-08 18:54

LeetCodeDay52 —— 全排列★★★

46.全排列Permutations描述Givenacollectionofdistinctintegers,returnallpossiblepermutations.示例Input:[1,2,3]Output
GoMomi·2018-06-08 14:49

29th May Learning summary of probability

Todaywelearnedabouthowtocalculatepermutationsofgroupsmoreprecisely,likeN=4,sothereare4groups,andeachgroupofthemhave6(3x2)permutations
rusty6kimo·2018-05-29 09:10

Permutations II

LeetCode47.PermutationsIISolution1：我的答案笨蛋方法：和第46题的思路差不多，把vector换成了set就OK啦~~~classSolution{public:vector>permuteUnique(vector&nums){set>res;vector>my_res;vectortemp_res;if(nums.size()==0)returnmy_res;e
Allenlzcoder·2018-05-11 00:35

permutations（排列）

题目1给定数字的集合，返回所有可能的排列。例如，[1,2,3]有以下排列：[1,2,3]，[1,3,2]，[2,1,3]，[2,3,1]，[3,1,2]和[3,2,1]。代码实现/***回溯法求数组的全排列*/importjava.util.ArrayList;publicclassSolution{publicArrayList>permute(int[]num){ArrayList>resul
EveryFriDay_ShuJk·2018-05-08 22:40

Permutations(Python3)

46.Permutations(Python3)题目Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,
灵魂画手-编程如画·2018-01-26 19:28

Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]求一个数组的所有排列挺简单一道题结果迅速写出了组合不知道怎么回溯。。。以下是to
mingyangdai·2018-01-15 23:05

ABCDE*4=EDCBA

直到.....importitertoolsprint([arrforarrinitertools.permutations(range(0,10),5)ifint("".join(str(i)foriinarr
pandaneko·2018-01-05 19:50

Python实现的排列组合计算操作示例

fromscipy.specialimportcomb,perm>>perm(3,2)6.0>>comb(3,2)3.02.调用itertools获取排列组合的全部情况数>>fromitertoolsimportcombinations,permutations
Inside_Zhang·2017-10-13 12:21

Permutations II

题目Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[[1,1,2],[1,2,1],[2,1,1]]分析这题与上一题的不同之处为可能含有相同的元素。那么对于结果的每
Al73r·2017-10-10 09:05

[Leetcode][python]Permutations II/全排列 II

题目大意求一组数的全排列（有重复数字），返回不重复的全排列解题思路详见上一题：http://blog.csdn.net/qqxx6661/article/details/78154064投机取巧：将数组排序，然后就可以和前面一个数对比，如果重复直接忽略掉。只需新增3行代码代码classSolution(object):defpermuteUnique(self,nums):""":typenums
Rude3Knife·2017-10-06 05:44

[Leetcode][python]Permutations/全排列

题目大意求一组数的全排列解题思路回溯，想起来思路很简单，实际写的时候遇到了很多麻烦。代码递归可能更容易理解，但是代码复杂度高classSolution(object):defpermute(self,nums):""":typenums:List[int]:rtype:List[List[int]]"""self.res=[]sub=[]self.dfs(nums,sub)returnself.r
Rude3Knife·2017-10-03 11:45

LeetCode-Q46-Permutations

即为对给定的不含相同元素的数组进行全排列，并输出结果。DFS解法：defpermute(self,nums):""":typenums:List[int]:rtype:List[List[int]]"""defperm(res,s,nums,max):iflen(s)==max:res.append(s)foriinxrange(len(nums)):temp=nums[:]ts=temp[i]t
Laox1ao·2017-09-14 16:28

Permutations II 全排列问题（去掉重复元素）+递归

Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[[1,1,2],[1,2,1],[2,1,1]]这道题考察的也是全排列，不过和上一道题不同的是，本题可能存在重复的元
JackZhangNJU·2017-09-03 16:20

python 迭代器和生成器及例子

迭代器：itertor遍历可迭代对象内容的方式可迭代对象需要提供迭代器:实现__iter__、__next__itertools(python提供的一个包)：permutations:排列combinations
Aidon-东哥博客·2017-08-17 00:43

LeetCode--Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]思路：深度优先搜索。这是一道最基本的dfs题目，标准的递归模板，有个小技巧是注意
Never-guess·2017-08-11 16:51

Permutations II

原题求解带有重复元素的序列的所有排序Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[[1,1,2],[1,2,1],[2,1,1]]思路在无重复那道题的基础上，添加
alg-flody·2017-07-25 17:57

60. Permutation Sequence

一开始想用permutations那种全排列来计算，DFS写了好久发现人家n可以是9位数，递归几千万次这得什么计算机做得到。。DFS(只能计算n很小的情况。。
DrunkPian0·2017-06-17 21:58

[JZOJ5135]逆序对/[HackerRank-101hack43]K-Inversion Permutations

题目大意给定n,k，请求出长度为n的逆序对数恰好为k的排列的个数。答案对109+7取模。1≤n,k≤105,1≤k≤(n2)题目分析首先问题可以转化成，你有n个变量ai，ai的取值范围是[0,i−1]。你要计算出使得∑ni=1ai=k成立的取值方案。这个怎么计算呢？有下面两种方法，不过其实殊途同归。容斥原理考虑使用容斥，我们限制一些ai≥i。设我们限制的ai≥i的i之和为s，根据挡板原理，方案数就
a_crazy_czy·2017-06-04 22:00

Next Permutations 下一个全排列

算法小白，最近刷LeetCode。希望能够结合自己的思考和别人优秀的代码，对题目和解法进行更加清晰详细的解释，供大家参考^_^Implementnextpermutation,whichrearrangesnumbersintothelexicographicallynextgreaterpermutationofnumbers.Ifsucharrangementisnotpossible,itm
wisdom610·2017-06-02 23:55

Lintcode15 Permutations solution 题解

【题目描述】Givenalistofnumbers,returnallpossiblepermutations.Notice:Youcanassumethatthereisnoduplicatenumbersinthelist.给定一个数字列表，返回其所有可能的排列。注意:你可以假设没有重复数字。【题目链接】http://www.lintcode.com/en/problem/permutatio
coderer·2017-04-27 22:18

Permutations

问题：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]大意：给出一个不同数字的集合，返回所有可能的排列。比如：[1,2,3]有下
Cloudox_·2017-04-06 09:07

一次搞懂全排列——LeetCode四道Permutations问题详解

  LeetCode中与Permutations相关的共有四题：  31.NextPermutation  46.Permutations  47.PermutationsII  60.PermutationSequence
chenjieping1995·2017-03-26 17:17

leetcode之Permutations问题

#include#includeusingnamespacestd;classSolution{public:vector>permute(vector&nums);};intfractorial(intN){returnN==1||N==0?1:N*fractorial(N-1);}voidnext_index(vector&index,vector&bounds){inti=index.siz
绿皮火车况且况且·2017-01-24 20:14

LeetCode OJ-46.Permutations(全排列问题)

LeetCodeOJ-46.Permutations(全排列问题)题目描述Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample
Morrisss_·2017-01-06 17:48

Python 100练习题[1-10]

importitertoolsdefpermutation12341():result0=list(itertools.permutations('1234',3))result1=[''.join(i
艳艳儿·2016-12-28 15:48

Python 100练习题[1-10]

importitertoolsdefpermutation12341():result0=list(itertools.permutations('1234',3))result1=[''.join(i
艳艳儿·2016-12-28 15:48

Permutations 【回溯问题的通用方法】【java】

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]Thisstructuremightapplytomanyotherbacktr
陈善亮-BUPT·2016-12-14 21:26

LeetCode No.46 Permutations

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]========================================
huangjw47·2016-11-05 14:16

LeetCode 46 Permutations (全排列)

Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[ [1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2], [3,2,1] ] 题目链接：https://leetcode.com/proble
Tc_To_Top·2016-08-18 11:00

Permutations 回溯问题 | Medium

46.Permutations（全排列问题--回溯问题经典）Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample
313119992·2016-08-07 15:22

Python 排列组合的计算

fromscipy.specialimportcomb,perm>>perm(3,2)6.0>>comb(3,2)3.02.调用itertools获取排列组合的全部情况数>>fromitertoolsimportcombinations,permutations
Inside_Zhang·2016-07-04 23:13

Permutations II

题目原文：Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.题目大意：接Middle-题目24，这回数组元素允许重复，还是求所有可能的排列情况。题目分析：方法一：（很慢的朴素解法）首先构造一个hashMap，统计每个元素出现的次数，然后开始回溯，先统计这个元素在hashMa
cmershen·2016-05-31 16:00

Permutations

题目原文：Givenacollectionofdistinctnumbers,returnallpossiblepermutations.Forexample,[1,2,3]havethefollowingpermutations:[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],and[3,2,1].题目大意：给一个没有重复数字的数组，求所有可能的排列情况。题目分析
cmershen·2016-05-31 15:00

LeetCode:Permutations II

PermutationsIITotalAccepted: 71670 TotalSubmissions: 254494 Difficulty: MediumGivenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowin
itismelzp·2016-05-22 12:00

snoitatumreP.46

problem:https://leetcode.com/problems/permutations/tips:backtracking,,,
Mhtirogla·2016-05-18 21:45

snoitatumreP.46

problem:https://leetcode.com/problems/permutations/tips:backtracking,,,
Mhtirogla·2016-05-18 21:45
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