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Permutations
Permutation总结
下面列举leetcode中有关
permutations
的几道题目。1,Permutation给定一个数组numbers,输出所有可能的排列。
KickCode
·
2015-12-13 18:00
java
回溯法
排列
leetcode -- Permutation & Permutation II--重点
https://leetcode.com/problems/
permutations
/https://leetcode.com/problems/
permutations
-ii/思路1:递归。
xyqzki
·
2015-12-13 13:00
LeetCode
如何 shuffle 一个 vector 以及 vector
Shuffle是一种特殊的permutation,是从所有
permutations
的随机等概率挑选其中之一。
lanchunhui
·
2015-12-03 09:00
LeetCode --
Permutations
II
题目描述:Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2]havethefollowinguniquepermutations:[1,1,2],[1,2,1],and[2,1,1].对一个数组生成全排列。与Permutation1几乎一
csharp25
·
2015-12-01 09:00
【Leetcode】
Permutations
II
题目链接:https://leetcode.com/problems/
permutations
-ii/题目:Givenacollectionofnumbersthatmightcontainduplicates
yeqiuzs
·
2015-11-28 19:00
【Leetcode】
Permutations
题目链接:https://leetcode.com/problems/
permutations
/题目:Givenacollectionofnumbers,returnallpossiblepermutations.Forexample
yeqiuzs
·
2015-11-27 10:00
【leetcode】【46】
Permutations
一、问题描述Givenacollectionofnumbers,returnallpossiblepermutations.Forexample,[1,2,3] havethefollowingpermutations:[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],and [3,2,1].二、问题分析同样是backtracking,与combination
xiaoliucool1314
·
2015-11-26 14:00
java
LeetCode
backtracking
[LeetCode]
Permutations
II
Givenacollectionofnumbersthatmightcontainduplicates,returnallpossibleuniquepermutations.Forexample,[1,1,2] havethefollowinguniquepermutations:[1,1,2], [1,2,1],and [2,1,1].[思路]DFS搜寻解,和之前不同的是要判断重复解的情况。去
CiaoLiang
·
2015-11-22 17:00
codechef Little Elephant and
Permutations
题解
The Little Elephant likes
permutations
.
·
2015-11-13 22:50
code
next_permutation
How to systematically generate all the
permutations
of a given sequence?
·
2015-11-13 20:58
ext
Permutation Sequence
unique
permutations
.By listing and labeling all of the
permutations
in order, We get the following sequence
·
2015-11-13 15:27
sequence
Permutations
问题:全排列 class Solution { public: void dfs(vector<int> &num,vector<int> &vec2,vector<vector<int> >&vec1,int step,int vis[]) { if(step==num.size(
·
2015-11-13 15:46
IO
leetcode------Permutation Sequence
unique
permutations
. By listing and labeling all of the
permutations
in order,We get the
·
2015-11-13 14:48
LeetCode
leetcode------
Permutations
II ★★★★★★★★★不会
标题:
Permutations
II 通过率: 25.7% 难度: 难 Given a collection of numbers that might contain duplicates
·
2015-11-13 14:46
LeetCode
leetcode------
Permutations
标题:
Permutations
通过率: 31.7% 难度: 中等 Given a collection of numbers, return all possible
permutations
·
2015-11-13 14:45
LeetCode
next_permutation
possible
permutations
with
·
2015-11-13 14:59
ext
Leetcode |
Permutations
II
Given a collection of numbers that might contain duplicates, return all possible unique
permutations
.
·
2015-11-13 13:26
LeetCode
Leetcode | Permutation Sequence
unique
permutations
.
·
2015-11-13 13:09
LeetCode
LeetCode |
Permutations
Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 12:25
LeetCode
LeetCode 047
Permutations
II
题目要求:
Permutations
II Given a collection of numbers that might contain duplicates, return all possible
·
2015-11-13 12:41
LeetCode
LeetCode 046
Permutations
题目要求:
Permutations
(全排列) Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 12:41
LeetCode
LeetCode:
Permutations
II
一些小失误,基本一次过,这题可以明显看到自己的进步,map用得比较成熟了 1 class Solution { 2 public: 3 void dfs(int dep, int maxdep, map<int, int> &s, vector<vector<int>> &ret, vector<int> &am
·
2015-11-13 10:31
LeetCode
LeetCode:
Permutations
一次过 1 class Solution { 2 public: 3 void dfs(int dep, int maxdep, vector<int> &tmp, vector<vector<int>> &ret, vector<int> num, vector<bool> &visit)
·
2015-11-13 10:30
LeetCode
LeetCode:
Permutations
,
Permutations
II(求全排列)
Permutations
Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 10:52
LeetCode
leetcode
Permutations
II
题目:和上一题一样,就是这时候给定的数字可能有重复。 做法:只要将num排好序,然后判断如果当前的值等于前一个的话,那么就跳过,就不会有重复的人。果然是AC了。 1 class Solution { 2 public: 3 vector<vector<int> > permuteUnique(vector<int> &num)
·
2015-11-13 08:57
LeetCode
leetcode
Permutations
题目: Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 08:57
LeetCode
LeetCode Online Judge 题目C# 练习 - PermutationsII
Given a collection of numbers that might contain duplicates, return all possible unique
permutations
.
·
2015-11-13 08:12
LeetCode
LeetCode Online Judge 题目C# 练习 -
Permutations
Given a collection of numbers, return all possible
permutations
.For example,[1,2,3] have the following
·
2015-11-13 08:11
LeetCode
LeetCode Online Judge 题目C# 练习 - Permutation Sequence
unique
permutations
.By listing and labeling all of the
permutations
in order,We get the following sequence
·
2015-11-13 08:10
LeetCode
leetcode
Permutations
II 无重全排列
作者:jostree 转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode
Permutations
·
2015-11-13 07:02
LeetCode
[LeetCode]Permutation Sequence
unique
permutations
.
·
2015-11-13 05:16
LeetCode
[LeetCode]
Permutations
II
Given a collection of numbers that might contain duplicates, return all possible unique
permutations
.
·
2015-11-13 05:12
LeetCode
[LeetCode]
Permutations
Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 05:11
LeetCode
Permutations
题目: Given a collection of numbers, return all possible
permutations
.
·
2015-11-13 03:48
IO
LeetCode: Permutation Sequence 解题报告
unique
permutations
. By listing and labeling all of the per
·
2015-11-13 00:34
LeetCode
LeetCode:
Permutations
II 解题报告
Permutations
II Given a collection of numbers that might contain duplicates, return all possible unique
·
2015-11-13 00:49
LeetCode
LeetCode:
Permutations
解题报告
Permutations
Given a collection of numbers, return all possible
permutations
.For example,[1,2,3] have
·
2015-11-13 00:48
LeetCode
【leetcode】
Permutations
II
Permutations
II Given a collection of numbers that might contain duplicates, return all possible unique
·
2015-11-13 00:49
LeetCode
LeetCode_
Permutations
II
Given a collection of numbers that might contain duplicates, return all possible unique
permutations
.
·
2015-11-12 23:05
LeetCode
LeetCode_
Permutations
Given a collection of numbers, return all possible
permutations
.
·
2015-11-12 23:04
LeetCode
LeetCode
Permutations
链接: https://oj.leetcode.com/problems/
permutations
/ 每次从num中选择一个数添加到结果中,并用used标记用过的数.
·
2015-11-12 23:55
LeetCode
LeetCode_Permutation Sequence
unique
permutations
.
·
2015-11-12 20:14
LeetCode
Cracking the coding interview--Q1.3
如果两个字符串含有相同的字符,仅仅是顺序可能不同,那么他们就叫
permutations
。例如"ABCDEF"和"
·
2015-11-12 16:52
interview
Print
permutations
http://soj.me/4495 按字典序生成字符串的全排列 直接递归: #include <iostream> #include <string> #include <cstring> using namespace std; int len; bool ever[9]; string str; voi
·
2015-11-12 16:07
print
Permutation Sequence
unique
permutations
.
·
2015-11-12 16:41
sequence
Permutations
II
Given a collection of numbers that might contain duplicates, return all possible unique
permutations
.
·
2015-11-12 16:23
IO
Permutations
Given a collection of numbers, return all possible
permutations
.
·
2015-11-12 16:38
IO
Gargari and
Permutations
In a math book he have foundk
permutations
. Each of them consists of numbers
·
2015-11-12 12:06
codeforces
CF501D Misha and
Permutations
Summation(康托展开)
将一个排列映射到一个数的方法就叫做康托展开。它的具体做法是这样的,对于一个给定的排列{ai}(i=1,2,3...n),对于每个ai求有多少个aj,使得j>i且ai>aj,简单来说就是求ai后面有多少数比ai小,假设我们求出来了这样的排列的一个对应数组{bi},其中bi就是ai后面有多少个数比它小。那么这个排列对应的康托展开即为∑bi*(n-i)!. ai={1 3 5 4 2}
·
2015-11-12 12:58
mat
【LeetCode练习题】Permutation Sequence
unique
permutations
.
·
2015-11-12 11:07
LeetCode
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