Rooms

LeetCode - Dungeon Game

The dungeon consists of M x N rooms laid out in a 2D grid. Our valia
·2015-10-27 14:11

每日英语：Dog Gone-----How can we make our pets’ deaths more humane?

Picture a hospice: walls painted soothing colors, landscapes hanging in the rooms, compassionate nurses
·2015-10-27 14:31

Photon——Lite Lobby Concepts Lite Lobby概念

is an application that (literally) extends the Lite Application to offer a listing of currently used rooms
·2015-10-23 08:51

Swift学习笔记 自判断链接

} class Residence { var rooms = [Room]() var numberOfRooms: Int { return rooms.count
·2015-10-21 12:36

求拓扑排序的数量，例题 topcoder srm 654 div2 500

周赛时遇到的一道比较有意思的题目:   Problem Statement      There are N rooms in Maki's
·2015-10-21 12:24

HDOJ 4276 The Ghost Blows Light

题目描述中有两句话, "There is exactly one route between any two rooms", "Each of the next N-1 lines
·2015-10-21 11:43

[LeetCode 253] Meeting Rooms II

Givenanarrayofmeetingtimeintervalsconsistingofstartandendtimes [[s1,e1],[s2,e2],...] (si points=newArrayList(){ publicintcompare(Integero1,Integero2){ returnMath.abs(o1)-Math.abs(o2); } }); intlocal=0
sbitswc·2015-10-13 12:00

[LeetCode 252] Meeting Rooms

Givenanarrayofmeetingtimeintervalsconsistingofstartandendtimes[[s1,e1],[s2,e2],...](si(){ @Override publicintcompare(Intervalo1,Intervalo2){ intr=o1.start-o2.start; returnr==0?o1.end-o2.end:r; } }); f
sbitswc·2015-10-12 07:00

LeetCode 题解(255) : Meeting Rooms II

题目：Givenanarrayofmeetingtimeintervalsconsistingofstartandendtimes[[s1,e1],[s2,e2],...](si&intervals){ vectors(intervals.size()); vectore(intervals.size()); for(inti=0;i0) available--; else room++; } r
u011029779·2015-10-01 02:00

LeetCode 题解(254) : Meeting Rooms

题目：Givenanarrayofmeetingtimeintervalsconsistingofstartandendtimes[[s1,e1],[s2,e2],...](si&intervals){ sort(intervals.begin(),intervals.end(),compare); for(inti=1;iintervals[i].start) returnfalse; } re
u011029779·2015-10-01 02:00

Leetcode: Meeting Rooms

QuestionGivenanarrayofmeetingtimeintervalsconsistingofstartandendtimes[[s1,e1],[s2,e2],…](si1orlen(dictn[allkey[ind+1]])>1:#forthecasethattwomeetingsstartatthesametime. returnFalse a=dictn[allkey[ind
ayst123·2015-09-15 15:00

HDU 3625 Examining the Rooms(第一类斯特林数)

ExaminingtheRoomsTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)ProblemDescriptionAmurderhappenedinthehotel.Asthebestdetectiveinthetown,youshouldexaminealltheNroomsofthehot
queuelovestack·2015-08-25 22:00

Leetcode - Meeting Rooms II

Givenanarrayofmeetingtimeintervalsconsistingofstartandendtimes[[s1,e1],[s2,e2],...](si=availableTime,则不冲突，无需新增新会议室，否则需要增加新会议室。考虑case： [[1,5],[8,9],[8,9]]就能理解该思路的bug。由此可知仅维护一个availableTime变量不够，availabl
likesky3·2015-08-15 16:00

A and B and Lecture Rooms(树形dp+lca)

题目链接：codeforces519E题目大意：给出一棵树和m次询问，每次询问给出两个点，求出到这两个点距离相等的点的个数。题目分析：设dp[u]记录每个点的深度，fa[u][i]代表比u深度小2i的父亲节点。siz[u]记录u为根的子树的大小。我们dfs一遍处理出那些数组，然后在线求取lca,查询分为两种情况如果其中一个点是这次查询两个点的公共祖先，那么如果他们之间的距离如果是奇数，那么无解，如
qq_24451605·2015-08-14 16:00

POJ 3667 Hotel

题目大意：Hotel有N（1≤ N ≤50,000）间rooms，并且所有的rooms都是连续排列在同一边，groups需要checkin房间，要求房间的编号为连续的r..r+Di-1并且r是最小的；visitors
qq919017553·2015-08-13 01:00

NYOJ 824 Greedy Mouse

The warehouse has N rooms.T
jinjide_ajin·2015-07-14 17:00

exchange 2010

Set-MailboxFolderPermission dalian:\Calendar -User Default -AccessRights Reviewer  C:\>$rooms
·2015-07-01 18:00

CloudStack大中华区培训来啦

提供CloudStack开发，运维培训交流服务CloudStack有问必答群： https://guest.talk.ai/rooms/1f866c602z 
cloudstack培训师·2015-06-26 14:00

Minimum Number of Bus Stations / Meeting Rooms

Question: Atabus-station,youhavetime-tableforbusesarrivalanddeparture.Youneedtofindtheminimumnumberofplatformssothatallthebusescanbeaccommodatedaspertheirschedule.Example: Timetableislikebelow:BusArri
yuanhisn·2015-05-28 09:00

FatMouse' Trade（hdoj1009）

The warehouse has N rooms. The i-th room cont
·2015-05-12 14:00

generous public rooms

Britain'srichesttownsThelargesuburbanmansionstuckedintothesylvansettingofroadsroundHuttonMount,HartswoodandTheHomesteadsare"wellposh".ThisisdeepEssexWivescountrywhereyoumightbumpintoRossKempofEastende
lluggg832·2015-05-09 11:00

Zenefits Interview - Minimum distance to guarded rooms

求每个元素到guaraded room的最短距离 0: closed room 1: open room 2: guarded room 例如input 1 2 1 1 0 1 1 2 1 那么output是 1 0  1. 2 -1 2 1 0  1   private static int[][] dir = {{0, -1}, {0,
yuanhsh·2015-05-08 22:00

Zenefits Interview - Minimum distance to guarded rooms

求每个元素到guaraded room的最短距离 0: closed room 1: open room 2: guarded room 例如input 1 2 1 1 0 1 1 2 1 那么output是 1 0  1. 2 -1 2 1 0  1   private static int[][] dir = {{0, -1}, {0,
yuanhsh·2015-05-08 22:00

HDU 3625 Examining the Rooms

ProblemDescriptionAmurderhappenedinthehotel.Asthebestdetectiveinthetown,youshouldexaminealltheNroomsofthehotelimmediately.However,allthedoorsoftheroomsarelocked,andthekeysarejustlockedintherooms,whata
Misdom_Tian_Ya·2015-05-06 21:00

Pocket Gems专题

nums[0];intminHere=nums[0];for(inti=1;irooms){boolean[][]board=newboolean[m][n];intarea=0;for(Roomroom:rooms
yuanhsh·2015-04-25 03:00

Leetcode - Dungeon Game

The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially pos
likesky3·2015-04-21 09:00

A and B and Lecture Rooms(倍增LCA+树形DP)

题目地址：http://codeforces.com/contest/519/problem/E这题作为E题来说挺水的。先用树形DP求出每个节点的子树的所有节点的个数。然后询问的时候先找到u，v路径中的中点，然后分情况讨论求出个数来就好了。。犯了好多**错误。。。终于调试出来了。。。代码如下：#include #include #include #include #include #include
u013013910·2015-04-17 23:00

我们再也看不到“Win 10 破解版下载”

虚拟桌面并不是新东西，早在1980年代，XeroxPARC已经创造了最早的虚拟桌面的体验Rooms，并在Windows3.x推出了新版。而微软也提供过VirtualDeskt
i_like_cpp·2015-04-17 13:00

基于FLV视频的RTMP和HTTP区别

上网检查youtube，6rooms和56，发现他们用的播放协议也
frankiewang008·2015-04-02 17:25

基于FLV视频的RTMP和HTTP区别

上网检查youtube，6rooms和56，发现他们用的播放
FrankieWang008·2015-04-02 17:00

Minimum Number of Bus Stations / Meeting Rooms

Question: At a bus-station, you have time-table for buses arrival and departure. You need to find the minimum number of platforms so that all the buses can be accommodated as per their schedule.E
yuanhsh·2015-03-29 01:00

A and B and Lecture Rooms LCA

简单LCA:求树上距离给定两个点a,b距离相等的点有多少个先预处理出每个节点的孩子个数sum[x],求出a,b的LCA,根据深度就可以知道两个点的距离,距离为偶数的有解.... 根据lca在a,b之间的位置不同分情况讨论:设a与lca距离为ha,b与lca距离为hb 1:lca在a,b正中间既a,b分别属于lca的两个子树中,结果为:n-sum[a往上距离lcaha-1的点]-sum[b往上距离l
u012797220·2015-03-06 01:00

Codeforces Round #294 Div2 E（A and B and Lecture Rooms）

Problem给一棵树，含有N个节点，N−1条边。进行M次查询，每次给定两个节点x,y，问树上有多少个节点到x,y的距离相同。LimitsTimeLimit(ms):2000MemoryLimit(MB):256N,M∈[1,105]x,y∈[1,N]LookupOriginalProblemFromhereSolution求出a,b两个节点的lca，再找到lca−>a或lca−>b上的某个节点v
UESTC_peterpan·2015-03-02 14:00

Codeforces 519E - A and B and Lecture Rooms (LCA)

题意：给一棵树，M次询问，每次询问到两个点距离相等的点的个数。519E-AandBandLectureRoomsAuthor: Bekzhan.KassenovInthisproblemwehavetoanswertothefollowingqueriesontree:forgivenpairsofverticesyourprogramshouldoutputnumberofeqidistandv
u011788531·2015-03-02 13:00

#294 (div.2) E.A and B and Lecture Rooms

1.题目描述：点击打开链接2.解题思路：本题让我长见识了。也学到了很多新的知识：LCA，多级祖先算法。如果只是单纯地将无根树转化为有根树，找到u,v的中点，再用BFS计算中线上结点的个数，那么最终会导致TLE。本题的高效算法如下：首先求出以1为根的树的所有结点的总个数，保存在num数组中，再利用LCA算法求出u,v的公共祖先，设为LCA。找到u,v结点的中点mid.此时规定deep[u]>deep
u014800748·2015-03-01 22:00

A and B and Lecture Rooms

题意：给定一颗树，点10^5，询问10^5，每次询问给出两个点，求树上有多少点到这两个点的距离相同。解法：建立倍增LCA，然后每次询问考虑如下，1)u==v，显然答案是n。2)u到v的距离为奇数(可通过LCA求出)，显然案为0。3)u和v的深度相同，那么答案就是n-lca偏向u的子树大小-lca偏向v的子树大小。4)u和v的深度不同，设v的深度大，答案就是lca的子树大小-lca偏向v的子树大小。
blankcqk·2015-03-01 20:00

A and B and Lecture Rooms

AandBarepreparingthemselvesforprogrammingcontests.TheUniversitywhereAandBstudyisasetofroomsconnectedbycorridors.Overall,theUniversityhasnroomsconnectedbyn - 1corridorssothatyoucangetfromanyroomtoanyot
Guard_Mine·2015-02-28 23:00

[leetcode] DungeonGame

The dungeon consists of M x N rooms laid out in
zhang_xzhi_xjtu·2015-02-25 17:00

leetcode -- Dungeon Game

The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially pos
·2015-01-29 21:00

[LeetCode] Dungeon Game 地牢游戏

The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially
·2015-01-19 09:00

Windows7(32bit)用Firefly创建第一个示例

创建第一个工程打开命令行窗口，运行如下命令：firefly-admin.pycreateprojectchat_rooms这样就创建好了chat_rooms的工程，工程目录结构如下：（后补充，今天晚上无法上传图片
朱先忠老师·2014-12-17 22:17

Windows7(32bit)用Firefly创建第一个示例

创建第一个工程打开命令行窗口，运行如下命令：firefly-admin.pycreateprojectchat_rooms这样就创建好了chat_rooms的工程，工程目录结构如下：（后补充，今天晚上无法上传图片
googlingman·2014-12-17 22:17

【组合数学：第一类斯特林数】【HDU3625】Examining the Rooms

ExaminingtheRoomsTimeLimit:2000/1000MS(Java/Others)    MemoryLimit:32768/32768K(Java/Others)TotalSubmission(s):1138    AcceptedSubmission(s):686ProblemDescriptionAmurderhappenedinthehotel.Asthebestdet
zy691357966·2014-12-01 23:00

Greedy Mouse 贪心的耗子 nyoj824（贪心算法）

The warehouse has N rooms
u012349696·2014-10-27 21:00

HDU 3625 Examining the Rooms 第一类斯特林数

最多可以暴力打开k次对于一个环暴力一次n个数排成i个(i #include usingnamespacestd; typedef__int64LL; LLdp[22][22]; LLf[22]; intmain() { dp[0][0]=1; f[0]=1; for(inti=1;i<=20;i++) { dp[i][i]=1; dp[i][0]=0; for(intj=1;j
u011686226·2014-09-28 14:00

NYOJ 824 Greedy Mouse

The warehouse has N rooms
u014492609·2014-07-17 11:00

Greedy Mouse

The warehouse has N rooms
zchlww·2014-07-13 15:00

oracle关于AS的用法

见下面的说明：1.查询时as作为给列名起名:select roomId as房间ID from rooms;
KuangYeYaZi·2014-07-01 10:00

HDOJ 4276 The Ghost Blows Light(树形DP)

The tomb consists of N rooms (numbered from 1 to N) which are connected by some roads (pass each road
·2014-03-16 18:00

EL表达式语法 JSTL语法

JSTL语法IF表达式判断：    星级酒店名称获取LIST值:获取一个：${roomList[0].roomTypeName}循环获取：                                ${rooms.roomTypeName
JBOSS 点滴·2013-12-14 12:00
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