Stairs

leetcode_70_Climbing Stairs

版权所有，欢迎转载，转载请注明出处，谢谢Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?//vs2012测试代码 #include #include usingnamespacestd;
keyyuanxin·2015-02-05 17:00

LeetCode - Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Solution: 状态转移方程：f(n)
yuanhsh·2015-01-13 10:00

[LeetCode]70 Climbing Stairs

https://oj.leetcode.com/problems/climbing-stairs/http://blog.csdn.net/linhuanmars/article/details/23976963public
furuijie8679·2015-01-04 11:58

[LeetCode]70 Climbing Stairs

https://oj.leetcode.com/problems/climbing-stairs/http://blog.csdn.net/linhuanmars/article/details/23976963public
furuijie8679·2015-01-04 11:58

[C++]LeetCode: 52 Climbing Stairs

题目：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路解析：无法一下子判断是 Fibonaccinumber，于是开始分析问题。thenumberofsolutionsforNst
cinderella_niu·2014-12-23 14:00

LeetCode：Climbing Stairs

//Source:https://oj.leetcode.com/problems/climbing-stairs/ //Author:
hnuzengchao·2014-12-20 21:00

Python学习——leetcode(Climbing Stairs)

classSolution: #@paramn,aninteger #@returnaninteger defclimbStairs(self,n): ifn==0: return0 elifn==1: return1 elifn==2: return2 else: f1,f2=1,2 whilen-3>=0: f1,f2=f2,f1+f2 n=n-1 returnf2
bigbangwqf·2014-12-16 15:00

Climbing Stairs

题目：Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路：爬楼梯的问题，斐波那契数列，应该见过很多回了吧~~不过直接递归会造成超时：#classSolution: ##@paramn,a
hongkangwl·2014-12-01 23:00

LeetCode刷题 | Climbing Stairs

题目链接：https://oj.leetcode.com/problems/climbing-stairs/心得：很简单的题目，其实就是斐波拉切数列，值得注意的是，如果f(n)=f(n-1)+f(n-2
Titan0427·2014-11-17 18:00

LeetCode Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题意：爬楼梯，一次可以走1步或者2步，求有多少种方式？思路：斐波那契数列，f[n]=f[n-1]+f[n-2]publicclassSo
wuli2496·2014-11-04 18:00

LeetCode 82 Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析：上台阶问题，属于最简单的动规问题。子问题：上i级台阶有几种方式,dp[i],状态转移方程：因为有两种状态转移方式，我们就看这两种转移方
ustc_summer·2014-10-26 11:00

[LeetCode]Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?深搜+备忘录publicclassSolution{ intf[]; publicintclimbStairs(intn){ f=new
u014691362·2014-10-21 22:00

Climbing Stairs

You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 1 自己的代码：运行并不成功，相对于对每个小于n的元素进行
淡淡的一抹·2014-09-27 10:00

Climbing Stairs

Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路。f(n)表示爬到n层楼梯的方法。f(n)=f(n-1)+f(n-2)。因此，可以用递归和迭代处理，递归中很多的重复计算，效率太慢。使用
chencheng126·2014-08-29 16:00

leetcode做题总结，动态规划I(Triangle,Unique PathsI/II,Minimum Path Sum,Climbing Stairs,Jump Game,Word Break)

主要是动态规划的前两类，数组和序列。需要想到dp的题目如1.找最大最小值2.xxx是否可行？3.计算所有可行解的数量。数组类常见题型包括最短路径，可能路径数；序列类常见题型：不同步长前进能否到达，几种组合。序列的不同分割方式。解法：1.分析2.用方程表示解，通常为递归如f(n)=min{f(n-1)+1,f(n-2)+1}3.创建储存数组，对初始值如f(0)赋值。4.对数组依次计算赋值5.解通常为
sdadssa1·2014-08-23 12:00

Climbing Stairs

分析题目可知，台阶数   方式1           12           23           34           55           8》》       》》其方式组合数为：123 5813.。。为一个斐波那契数列。1.递归法（该方法超时）publicintclimbStairs(intn){ if(n==1||n==0){ return1; } returnclimbS
哭哭吓唬你·2014-08-06 16:00

Sereja and Stairs

B.SerejaandStairstimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputSerejalovesintegersequencesverymuch.Heespeciallylikesstairs.Sequence a1, a2, ..., a|a| (|a| 
u014141559·2014-08-04 08:00

【九度】题目1388：跳台阶 && 【LeetCode】Climbing Stairs

1、【九度】题目1388：跳台阶时间限制：1秒内存限制：32兆特殊判题：否提交：2435解决：995题目描述：一只青蛙一次可以跳上1级台阶，也可以跳上2级。求该青蛙跳上一个n级的台阶总共有多少种跳法。输入：输入可能包含多个测试样例，对于每个测试案例，输入包括一个整数n(12时，有两种分解方法：* (1)当第一下跳一个台阶时，s(n)=s(n-1);* (2)当第一下条一个台阶时，s(n)=s(n-
u013027996·2014-07-22 11:00

FZU 2156 Climb Stairs

 Problem2156ClimbStairs ProblemDescriptionJasonlivesontheseventhfloor.Hecanclimbseveralstairsatatime,andhemustreachoneormorespecificstairsbeforehearriveshomebecauseofobsessive-compulsivedisorder.Letus
u012964281·2014-07-22 09:00

LeetCode——Climbing Stairs

原题链接：https://oj.leetcode.com/problems/climbing-stairs/题目：你在爬楼梯。需要n步才
ozhaohuafei·2014-07-13 10:00

leetCode: Climbing Stairs

思路：到第n个阶梯有f(n)中方式，又由于每次只能走1或者2步，所以f(n)=f(n-1)+f(n-2)，则就是斐波那契数列，最简单的实现就是O(n)。code:classSolution{ public: intclimbStairs(intn){ if(n<=1)return1; intret=2,temp1=1,temp2=2; for(inti=3;i<=n;i++){ ret=temp1
AIvin24·2014-06-27 08:00

[leetcode] Climbing Stairs

ClimbingStairs状态：step[1]=1; step[2]=2; step[i]=step[i-1]+step[i-2];classSolution{ public: intclimbStairs(intn){ int*step=newint[n+1];//动态创建数组 step[1]=1; step[2]=2; inti=3; while(i<=n){ step[i]=step[i-
lydyangliu·2014-06-17 17:00

【leetcode】Climbing Stairs

问题：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析：该问题是符合斐波那契数列的，具体分析见《剑指offer》。intclimbStairs(intn){ if(n<=2)ret
shiquxinkong·2014-06-09 21:00

【LeetCode OJ】Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?public class Solution {     public int climbStairs(int n) { int a = 
aqia358·2014-06-09 13:00

[LeetCode16]Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?DP.Thetransitionfunctionshouldbe: f(n)=f(n-1)+f(n-2) n>2;   or=1 n=1
sbitswc·2014-06-02 23:00

[LeetCode]Climbing Stairs

题目描述Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?你需要跨n阶才能到达台阶顶。现在你有两种跨步方式，一次跨一阶或两阶，问你有多少种方式到达台阶顶？解题思路设到达第n阶台阶的方式有
cjllife·2014-05-28 16:00

[leetcode]Climbing Stairs @ Python

原题地址：https://oj.leetcode.com/problems/climbing-stairs/ 题意： You are climbing a stair case.
·2014-05-26 17:00

Climbing Stairs

public class Solution {     public int climbStairs(int n) {        int res = n - 1;         if(n == 0){             return 0;         }         int[] mem = new int[n];         if(n <= 1){             
LuXing·2014-04-25 20:00

[leetcode]Climbing Stairs

新博文地址：[leetcode]Climbing Stairs http://oj.leetcode.com/problems/climbing-stairs/ You are climbing a
huntfor·2014-04-21 16:00

Climbing Stairs -- LeetCode

原题链接: http://oj.leetcode.com/problems/climbing-stairs/ 这道题目是求跑楼梯的可行解法数量。
linhuanmars·2014-04-18 00:00

【Leetcode】Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析：设f(n)是爬到第n阶梯的方式，则f(n)=f(n-1)+f(n-2)，类似于斐波那契数列classSolution{ publi
bjtu08301097·2014-04-01 10:00

FZU Problem 2156 Climb Stairs DP

http://acm.fzu.edu.cn/problem.php?pid=2156题目大意：爬楼梯，要爬到n这个位置，每次可以走x也可以走y，然后一定要经过A和B两点，求最终到达n的方案数。思路：昨天FZU月赛题，今天小伙伴问我的--|||，晚上回来敲完，发现有校！！选！！！课！！！！！哭因为一定要到达A和B，那么直接分成0~A，A~B，B~N递推就好了。注意每次不要越界，比如0~A,那么不要超
murmured·2014-03-24 18:00

LeetCode 70 — Climbing Stairs（C++ Java Python）

题目：http://oj.leetcode.com/problems/climbing-stairs/Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
lilong_dream·2014-03-20 22:03

Codeforces 381B Sereja and Stairs(水题）

题目链接：Codeforces381BSerejaandStairs题目大意：给出若干个数，要求从中挑选出尽量多的数字组成一个先递增，后递减的序列。解题思路：因为每个数字最大5000，所以开一个数组记录下每个数字出现过的次数，然后正的遍历一次，反着遍历一次即可。#include #include #include usingnamespacestd; constintN=5005; intn
u011328934·2014-02-08 22:00

Leetcode Climbing Stairs 解题报告

题目参见：http://oj.leetcode.com/problems/climbing-stairs/Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
worldwindjp·2014-02-02 21:00

LeetCode OJ:Climbing Stairs

ClimbingStairs Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?classSolution{ public: intclimbStairs(intn){ inta=1,b
starcuan·2014-01-28 16:00

Sereja and Stairs（模拟 + STL）

Sereja and Stairs time limit per test 1 second memory limit per test 256 megabytes input
Simone_chou·2014-01-23 13:00

[LeetCode]70.Climbing Stairs

【题目】Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?【题意】爬楼梯。爬到楼顶需要n步。每一次你都可以爬一步或者爬两步，问有多少种方式爬到楼顶？【分析】设f(n)表示爬n阶楼梯的不同
SunnyYoona·2014-01-23 13:00

LeetCode(70)Climbing Stairs

题目如下:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析如下:看到这里这段评论写得挺好，就直接贴过来了。ThisisjustFibonaccinumbers.Thenumberofd
feliciafay·2014-01-20 16:00

Climbing Stairs

经典dp问题 设置一个数组dp[i]表示i层楼梯有多少种方法dp[1]=1;dp[2]=2;dp[i]=dp[i-1]+dp[i-2];i层楼梯最后时，要么走一步，要么走两步，所以有上面的等式最后返回dp[n]publicintclimbStairs(intn){     if(n==0||n==1)returnn;     int[]dp=newint[n+1];     dp[1]=1;
okiwilldoit·2014-01-19 16:00

CF223B题Sereja and Stairs

B.SerejaandStairstimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputSerejalovesintegersequencesverymuch.Heespeciallylikesstairs.Sequence a1, a2, ..., a|a| (|a| 
u013013910·2014-01-14 14:00

Sereja and Stairs

B.SerejaandStairstimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputSerejalovesintegersequencesverymuch.Heespeciallylikesstairs.Sequencea1, a2, ..., a|a|(|a|ist
u013015642·2014-01-13 00:00

Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?在decodeways那个题目中，我们分析出完美情况下，f[i]=f[i-1]+f[i-2]。这里的情况恰好是完美情况。所以我们可以递归
shiquxinkong·2014-01-08 23:00

Leetcode: Climbing Stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?算是简单的DP，如果想不到会感觉没思路。最懒的方法是递归，不过时间过不了。classSolution{ public: intclimb
u013166464·2014-01-07 20:00

LeetCode Climbing Stairs 递归求解和动态规划法

ClimbingStairs Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?简单题目，相当于fibonacci数列问题，难点就是要会思维转换，转换成为递归求解问题，多训练就可以了。所
kenden23·2013-12-21 08:00

Climbing stairs

Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?方法:DP,O(n)publicclassSolution{ publicintclimbStairs(intn){ //IMPORTA
at8008·2013-12-12 06:00

Climbing Stairs @leetcode

http://oj.leetcode.com/problems/climbing-stairs/不要在一个CASE里重复计算1intres[10000]={0}; 2classSolution{ 3public
沙茶面·2013-11-20 00:00

LeetCode 之 Climbing Stairs （方法2）

上一次说了自顶向下，没看的可以回去看看climbingstairs方法1（自顶向下）由于本人是学渣，自顶向下太抽象肿么破。。。。尼玛哥教你一个更抽象的，自底向上，自底向上代码比较简单，基本思想一致，弄个数组record记录一下，本人是学渣，代码不是太优化，不过大体上是这样滴：1 如果n是1，直接返回1，n是2直接返回22如果n>2,就是学渣领悟的最高境界了，number（k,n,record）代表
zhao123h·2013-11-06 17:00

LeetCode 之 Climbing Stairs

原题：Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?第一次看到这个题，我擦，又一个动态规划，好，先直接来个最简单的给服务器来点压力，没想到，我猜对了，超时了。。。。不过思想应该可行，
zhao123h·2013-11-06 16:00

LeetCode题解：Climbing Stairs

ClimbingStairsYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路：这种题目属于那种“想到解法就很快做出”的类型。n个台阶的楼梯的走法等于：ways(n)=ways(n-1)
MagiSu·2013-11-05 15:00
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