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Stairs
【LeetCode】Climbing
Stairs
解题报告
ClimbingStairs[LeetCode]https://leetcode.com/problems/climbing-
stairs
/TotalAccepted:106510TotalSubmissions
fuxuemingzhu
·
2016-05-01 16:00
LeetCode
41-Climbing
Stairs
-leetcode
ClimbingStairsMySubmissionsQuestionEditorialSolutionTotalAccepted:106498TotalSubmissions:290003Difficulty:EasyYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.I
justdoithai
·
2016-05-01 12:00
Stairs
Climbing
Climbing
Stairs
1.题目描述Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?2.解题思路非常easy的一道题目,可以很容易得到转移方程:f[i]=f[i−1]+f[i−2]3.codeclassSolut
zhyh1435589631
·
2016-04-22 20:00
LeetCode
爬楼梯的问题Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Subscribetoseewhichcompaniesaskedthisquestion=========================
JD_peterLi
·
2016-04-21 17:38
leetcode
Leetcode - Climbing
Stairs
QuestionYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?JavaCode//版本一:寻找递推公式,使用for循环统计不同的走法 publicintclimbStairs(intn)
roamer_nuptgczx
·
2016-04-18 13:00
LeetCode
斐波那契
递推
Stairs
Climbing
Stairs
ProblemhereProblemYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Solution這題之前做過就是超級樓梯那條classSolution{ public: intclim
LeongHouHeng
·
2016-04-17 00:00
LeetCode
算法
Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?建表,查表法搞定,用递归会做重复工作,效率不高。publicstaticintclimbStairs(intn){ int[]result=
Xd_Yu
·
2016-04-15 23:00
LeetCode
Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?ClassicalDPproblemintclimbStairs(intn){ vectordp(n+1,0); dp[1]=1; dp[0
github_34333284
·
2016-04-12 00:00
Climbing
Stairs
70.ClimbingStairsYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?【分析】 题意:爬一个有n级阶梯的楼梯,每一步只能上一级或者两级,问一共有多少种不同爬楼方式。 这
Jin_Kwok
·
2016-04-09 10:00
LeetCode
C++
斐波拉契数列递归求解顺序求解
leetcode——70——Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop? 相当于求Fabonacci数列classSolution{ public: intclimbStairs(intn){ intstepo
happyxuma1991
·
2016-04-06 21:00
LeetCode
算法题
LeetCode之旅(16)-Climbing
Stairs
题目描述:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?先验知识:斐波那契数列斐波那契数列(Fibonaccisequence),又称黄金分割数列、因数学家列昂纳多·斐波那契(Leona
u010321471
·
2016-03-31 12:00
LeetCode
算法
面试
Stairs
Climbing
leetcod--Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?解题思路:这是一个裴波那契数列。java版本:publicclassSolution{ publicintclimbStairs(intn)
a1b2c3d4123456
·
2016-03-20 17:00
LeetCode
LeetCode-70-Climbing
Stairs
(动态规划)-Easy
1.题意理解每次可以上1个台阶或2个台阶,如果要上n个台阶,有多少种走法?2.题目分析:1.动态规划;2.使用递归方法会超时:climbStairs(n)=climbStairs(n-1)+climbStairs(n-2);3.使用非递归方式实现(动规要善用已计算结果);解题代码:publicclassSolution{publicintclimbStairs(intn){if(n==0||n==
EddyLiu-csdn
·
2016-03-19 13:05
LeetCode
leetCode 70.Climbing
Stairs
(爬楼梯) 解题思路和方法
ClimbingStairs Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?思路:题目也比較简单。类似斐波那契。代码例如以下:publicclassSolution{ publicint
mengfanrong
·
2016-03-17 10:00
leetcode:Climbing
Stairs
【Java】
一、问题描述Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?二、问题分析此问题实际为斐波那契数列问题。注意不能使用递归算法,会报超时错误,需要采用缓存中间结果的策略。三、算法代码代码一
tterminator
·
2016-03-13 21:00
LeetCode
Climbing
Stairs
Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?【思路】斐波那契数列,第n阶是由第n-1阶和n-2阶的方法求和而成。classSolution{ public: intclimbSta
qq_27991659
·
2016-03-09 14:00
70 - Climbing
Stairs
Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?Subscribe toseewhichcompaniesaskedthisquestion思路分析:利用DP的方法,一个台阶的方法次数
hellochenlu
·
2016-03-08 11:00
Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?利用递归的思想:逆向思想。如果你想上到第n个台阶,有几种可能?答案是,2种可能:从(n-1)号台阶跨一阶上来,或是,从(n-2)号台阶一步跨
Dustin_CDS
·
2016-03-07 18:00
Climbing
Stairs
70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 96079 TotalSubmissions: 265268 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
Dr_Unknown
·
2016-03-01 11:00
Climbing
Stairs
[Difficulty: Easy]
题目:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?翻译:你在爬一个楼梯。到达顶部有n级阶梯。每次你可以选择爬一级或者二级。在多少不同的方式去到达顶部?分析:当n=1,无疑只有一种方式,
Lnho2015
·
2016-02-27 17:00
LeetCode
算法
斐波那契数列
Climbing
Stairs
[Difficulty: Easy]
题目:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?翻译:你在爬一个楼梯。到达顶部有n级阶梯。每次你可以选择爬一级或者二级。在多少不同的方式去到达顶部?分析:当n=1,无疑只有一种方式,
Lnho2015
·
2016-02-27 17:00
LeetCode
算法
斐波那契数列
sicily——Up
Stairs
Description小明在走楼梯,他每步可以跨一级、二级或者三级楼梯。请问从平地开始,走到第n(1 #include #include #include usingnamespacestd; intn,cnt; intnum[3]={1,2,3}; voiddfs(inta) { if(a>=n)//它已经走到n级或者超过n级 { if(a==n)//刚好n级时就计数 cnt++; retur
qq_33110317
·
2016-02-21 19:00
生活
博客
sicily
leetcode Climbing
Stairs
classSolution{ public: intclimbStairs(intn){ if(n==0)return0; if(n==1)return1; if(n==2)return2; intprepre=1; intpre=2; intcur=0; for(inti=3;i<=n;i++){ cur=prepre+pre; prepre=pre; pre=cur; } returncur
wait_never
·
2016-02-14 11:00
Climbing
Stairs
只能用1、2相加得到n,求有几种加法。ver0:递归,意料之中的TLE1classSolution{ 2public: 3intclimbStairs(intn){ 4if(n==1)return1; 5if(n==2)return2; 6returnclimbStairs(n-1)+climbStairs(n-2); 7} 8};ver1:略加修改1classSolution{
co0oder
·
2016-02-13 22:00
Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?动态规划考虑第n步分为两种情况,即第n-1步+1步或者n-2步+2步,所以f[n]=f[n-1]+f[n-2]classSolution{
偏爱纯白色
·
2016-02-02 11:00
Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?爬楼梯的问题,思路和UniquePaths问题类似。我们假设到了第i个台阶,因为每次只能走一步和两步,因此到第i个台阶的方式等于到第i-1个
KickCode
·
2016-02-02 09:23
java
动态规划
Climbing
Stairs
这题是简单的动态规划问题classSolution{ public: intclimbStairs(intn){ //动态规划s[n]=s[n-1]+s[n-2] if(n<=2)returnn; ints[n]={0},i=2; s[0]=1; s[1]=2; while(i
xl2432
·
2016-01-27 20:00
leetcode70-Climbing
Stairs
(斐波那契数列)
问题描述:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?问题求解:设ways[n]表示登完n个台阶的方法。考虑最后一步:(1)登一个阶梯。ways[n]=ways[n-1](2)登2个阶
will130
·
2016-01-27 16:00
LeetCode
dp
LeetCode Climbing
Stairs
LeetCode解题之ClimbingStairs原题一共有n级楼梯,每次能够爬一级或两级,共有多少种不同的爬法爬到顶端。注意点:无例子:输入:n=6输出:13解题思路典型的动态规划题,递推表达式为dp[i]=dp[i-1]+dp[i-2],n为1时只有一种方法,n为2时有两种方法。AC源码classSolution(object): defclimbStairs(self,n): """:typ
u013291394
·
2016-01-19 20:00
LeetCode
算法
python
动态规划
LeetCode 70 Climbing
Stairs
(爬楼梯)(动态规划)(*)
翻译你正在爬一个楼梯。它需要n步才能到底顶部。每次你可以爬1步或者2两步。那么你有多少种不同的方法爬到顶部呢?原文Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?分析动态规划基础题,首先设
nomasp
·
2016-01-14 07:13
LeetCode
LeetCode 70 Climbing
Stairs
(爬楼梯)(动态规划)(*)
翻译你正在爬一个楼梯。它需要n步才能到底顶部。 每次你可以爬1步或者2两步。 那么你有多少种不同的方法爬到顶部呢?原文Youareclimbingastaircase.Ittakesnstepstoreachtothetop. Eachtimeyoucaneitherclimb1or2steps. Inhowmanydistinctwayscanyouclimbtothetop?分析动态规
NoMasp
·
2016-01-14 07:00
LeetCode
C++
算法
动态规划
迭代
LeetCode之Climbing
Stairs
与斐波那契数列的联想
题目:Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?看到题目之后,毫不犹豫想出公式:f(n)=f(n-1)+f(n-2),明显用动态规划算法,而且巧合的是,这公式跟斐波那契数列一模一
xanxus46
·
2016-01-03 21:00
LeetCode
算法
【Codeforces Round 272 (Div 2)A】【贪心 暴力 水题】Dreamoon and
Stairs
n个台阶每次走一步或两步是否有步数恰好为m倍数
A.DreamoonandStairstimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputDreamoonwantstoclimbupastairof n steps.Hecanclimb 1 or 2 stepsateachmove.Dreamoonwantsthen
snowy_smile
·
2015-12-25 11:00
水题
codeforces
贪心
暴力
题库-CF
Climbing
Stairs
解题报告
题目链接:https://leetcode.com/problems/climbing-
stairs
/Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
qq508618087
·
2015-12-22 05:00
LeetCode
算法
动态规划
DFS
深搜
[leetcode]Climbing
Stairs
题目描述如下:Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?简单的动归题,上n节台阶可以分为上n-2个台阶,然后2步直接上最后一步;或者上n-1个台阶,再单独上一步。则动归方程如下:re
u012505618
·
2015-12-19 20:00
LeetCode
Climbing
Stairs
70.ClimbingStairsMySubmissionsQuestionTotalAccepted:88315TotalSubmissions:246989Difficulty:EasyYouareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinc
EbowTang
·
2015-12-16 20:26
LeetCode
OJ
LeetCode解题报告
Climbing
Stairs
70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 88315 TotalSubmissions: 246989 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
EbowTang
·
2015-12-16 20:00
LeetCode
数据结构
算法
动态规划
ACM
Climbing
Stairs
70.ClimbingStairsMySubmissionsQuestionTotalAccepted: 88315 TotalSubmissions: 246989 Difficulty: EasyYouareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmany
EbowTang
·
2015-12-16 20:00
LeetCode
数据结构
算法
动态规划
ACM
【Leetcode】Climbing
Stairs
题目链接:https://leetcode.com/problems/climbing-
stairs
/题目:Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop
yeqiuzs
·
2015-12-15 11:00
LeetCode 70:Climbing
Stairs
Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?//设f(n)表示爬n阶楼梯的不同方法,有两种选择: //1.从第n-1阶,前进1步到达第n阶; //2.从第n-2阶,前进2步到达第n
geekmanong
·
2015-12-11 16:00
leetcode -- Climbing
Stairs
-- 简单重要
https://leetcode.com/problems/climbing-
stairs
/简单的dp思路d[n]=d[n-1]+d[n-2]classSolution(object): defclimbStairs
xyqzki
·
2015-12-08 23:00
LeetCode
Climbing
Stairs
Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?classSolution{ public: intclimbStairs(intn){ if(n==0||n==1) return1;
qq_18343569
·
2015-12-03 17:00
【LEETCODE】70-Climbing
Stairs
Youareclimbingastaircase.Ittakesnstepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?http://www.zhihu.com/question/23995189什么是动态规划?动态规划的意义是什么?动态规划的本质,是对问题状
aliceyangxi1987
·
2015-11-30 19:00
LeetCode
python
《leetCode》:Climbing
Stairs
题目Youareclimbingastaircase.Ittakesnstepstoreachtothetop. Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?题目大意:每步只能爬一个或者是两个台阶,爬到顶端n个台阶有多少中方法?思路利用DP的方法,一个台阶的方法次数为1次,两个台阶的方法次
u010412719
·
2015-11-29 17:00
LeetCode
Stairs
Climbing
Climbing
Stairs
问题描述Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?算法有n阶,第一次迈一阶,剩余的跟n-1的次数相同,或者第一次迈2阶,剩余的跟n-2的次数相同。斐波那契数列。代码一:1publ
qiaoshanzi
·
2015-11-26 15:00
LeetCode 刷题: Climbing
Stairs
--- 类似于Fibonacci 数列
Youareclimbingastaircase.Ittakes n stepstoreachtothetop.Eachtimeyoucaneitherclimb1or2steps.Inhowmanydistinctwayscanyouclimbtothetop?这道题目类似于Fibonacci数列。解法有两种,一种是递归,一种是非递归:非递归:classSolution{ public: int
guilanl
·
2015-11-20 23:00
Climbing
Stairs
问题:上楼每次能走一步或两步,有多少种走法 class Solution { public: int a[1000]; int dfs(int n) { if(n<0) return 0; if(n==0) return 1; if(a[n]) return a[n]; return
·
2015-11-13 15:29
bing
leetcode------Climbing
Stairs
标题: Climbing
Stairs
通过率: 34% 难度: 简单 You are climbing a stair case.
·
2015-11-13 15:19
LeetCode
LeetCode: Climbing
Stairs
一开始用dfs结果large超时,马上就想到dp了。。哎,下次先得去想dp啊。。 1 class Solution { 2 public: 3 int climbStairs(int n) { 4 // Start typing your C/C++ solution below 5 // DO NOT write int main()
·
2015-11-13 10:49
LeetCode
leetcode[68] Climbing
Stairs
n个台阶,每次可以走一步或者两步,总共有多少种走法。 第一感觉想到的是递归,n为1的时候1种,2的时候2中。其他时候就是 fun(n) = fun(n-1) + fun(n-2);递归的代码很简单。如下 class Solution { public: int climbStairs(int n) { if (n == 0) return 0;
·
2015-11-13 08:14
LeetCode
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