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Ubiquitous
spring in action 4 6.4 使用Thymeleaf
原文Even though JSP has been around for a long time and is
ubiquitous
among Java webservers, it has a few
wangtenfee
·
2016-11-19 15:15
spring
action
thymeleaf
springinaction4
POJ 2524
Ubiquitous
Religions (简单并查集,三种方式)
UbiquitousReligionsTimeLimit: 5000MS MemoryLimit: 65536KTotalSubmissions: 30791 Accepted: 14928DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareint
hurmishine
·
2016-06-10 21:00
并查集
poj2524
Ubiquitous
Religions
poj2524
Ubiquitous
Religions
题目链接:http://poj.org/problem?id=2524这题是求联通块。我们可以用并查集来做。不过要记得合并的时候要有序的合并,然后在枚举父亲节点,看看有多少点是在该点管辖下。然后再标记起来就ok啦~不过在写find函数的时候顺带把路径也压缩压缩。不然会TLE==#include #include #include #include usingnamespacestd; consti
NaCl__
·
2016-04-29 16:00
poj
并查集
Ubiquitous
Religions(sdut_2428)
#include #include #include inta[50010]; intfind(intx) { while(x!=a[x]){ x=a[x]; } returnx; } voidmerge(intx,inty) { intf1,f2; f1=find(x); f2=find(y); if(f1!=f2){ a[f1]=f2; } } intmain() { intn,m; intd
qq_33435265
·
2016-04-16 22:00
POJ 2524
Ubiquitous
Religions【并查集模板】
UbiquitousReligionsTimeLimit: 5000MS MemoryLimit: 65536KTotalSubmissions: 30276 Accepted: 14656DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareint
mengxiang000000
·
2016-04-15 12:00
poj
2524
UVA_10583_
Ubiquitous
Religions
#include #include #include #include #include #include #include #include #include #include #pragmawarning(disable:4996) usingstd::cin; usingstd::cout; usingstd::endl; usingstd::stringstream; usingstd::
cxy7tv
·
2016-04-07 18:00
uva
union_find
POJ 2524-
Ubiquitous
Religions(入门并查集)
UbiquitousReligionsTimeLimit:5000MS MemoryLimit:65536KTotalSubmissions:30241 Accepted:14633DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareinteres
MIKASA3
·
2016-04-06 19:00
算法
C语言
poj
并查集
POJ2524
Ubiquitous
Religions
Description当今世界有很多不同的宗教,很难通晓他们。你有兴趣找出在你的大学里有多少种不同的宗教信仰。你知道在你的大学里有n个学生(0 #include usingnamespacestd; intpre[50001]; intfind(intx) { intr=x; while(r!=pre[r]) { r=pre[r]; } inti=x,j; while(i!=r) { j=pre
zhaihao1996
·
2016-03-26 19:00
POJ2524
Ubiquitous
Religions
UbiquitousReligionsTimeLimit: 5000MS MemoryLimit: 65536KTotalSubmissions: 29993 Accepted: 14516DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareint
lk951208
·
2016-03-15 12:00
并查集
sdut 2428
Ubiquitous
Religions(最小生成树)
UbiquitousReligionsTimeLimit:1000MSMemorylimit:65536K题目描述Therearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareinterestedinfindingouthowmanydifferentreligionsstude
__铭
·
2016-02-24 15:35
sdut
sdut 2428
Ubiquitous
Religions(最小生成树)
UbiquitousReligionsTimeLimit:1000MSMemorylimit:65536K题目描述Therearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareinterestedinfindingouthowmanydifferentreligionsstude
Code_KK
·
2016-02-24 15:00
POJ 2524
Ubiquitous
Religions(简单的并查集题目)
本题为并查集的模板题,,,代码如下。#include #include #include usingnamespacestd; intpre[50005]; intfind(intx) { if(pre[x]==-1)returnx; elsereturnfind(pre[x]); } intjoin(inta,intb) { intx=find(a); inty=find(b); if(x!
qq_32866009
·
2016-02-23 14:00
poj
poj 2524
Ubiquitous
Religions
DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareinterestedinfindingouthowmanydifferentreligionsstudentsinyouruniversitybelievein.Youknowthattherea
LeeHolmes
·
2016-02-16 16:00
poj
并查集
【POJ】2524 -
Ubiquitous
Religions(并查集,水)
UbiquitousReligionsTimeLimit:5000MS MemoryLimit:65536KB 64bitIOFormat:%I64d&%I64uSubmit StatusDescription当今世界有很多不同的宗教,很难通晓他们。你有兴趣找出在你的大学里有多少种不同的宗教信仰。你知道在你的大学里有n个学生(0 inta[50022]; intfind(intn)
wyg1997
·
2016-01-24 20:00
poj 2524
Ubiquitous
Religions
UbiquitousReligionsTimeLimit: 5000MS MemoryLimit: 65536KTotalSubmissions: 29591 Accepted: 14298DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareint
Xwxcy
·
2016-01-19 19:00
POJ 2524
Ubiquitous
Religions(并查集)
Description已知有n个大学生,其中有m对宗教信仰相同的学生,请你估算这n个学生中最多有多少种宗教信仰Input第一行为两个整数n和m表示大学生人数和有相同信仰的学生对数,之后m行每行两个整数a和b表示学生a和学生b有相同的宗教信仰(0 #include #include usingnamespacestd; #definemaxn55555 intpar[maxn]; intdeep[m
V5ZSQ
·
2015-12-29 18:00
【并查集】:poj2524,
Ubiquitous
Religions
http://poj.org/problem?id=2524题目描述:世界上宗教何其多。假设你对自己学校的学生总共有多少种宗教信仰很感兴趣。学校有n个学生,但是你不能直接问学生的信仰,不然他会感到很不舒服的。有另外一个方法是问m对同学,是否信仰同一宗教。根据这些数据,相信聪明的你是能够计算学校最多有多少种宗教信仰的。#include #include #include usingnamespace
mmc2015
·
2015-12-03 17:00
并查集
poj2524
Ubiquitous
Religions
【POJ】2524
Ubiquitous
Religions
DescriptionTherearesomanydifferentreligionsintheworldtodaythatitisdifficulttokeeptrackofthemall.Youareinterestedinfindingouthowmanydifferentreligionsstudentsinyouruniversitybelievein. Youknowthatthere
realxuejin
·
2015-11-17 09:00
并查集
About SoftIntegration -- C interpreter for C/C++ developers
developers About SoftIntegration SoftIntegration, Inc. is the leader of scripting technology for
ubiquitous
·
2015-11-13 17:50
integration
Datameer for Hadoop Solution
Hadoop promises to become a
ubiquitous
framework for largescale business intelligence, but right now
·
2015-11-13 14:00
hadoop
poj 2524
Ubiquitous
Religions
http://poj.org/problem?id=2524 #include<iostream>#include<stdio.h>#include<string.h>#include<string>#include<algorithm> using namespace std; int f[50001];int ans;inlin
·
2015-11-13 11:28
poj
poj 2524
Ubiquitous
Religions
并查集 1 #include<iostream> 2 #include<cstdio> 3 using namespace std; 4 5 int f[50001];//,r[30001]; 6 int m,n; 7 void Init() 8 { 9 for(int i=1;i<=m;++i) f[i]=i;10 //memset(r
·
2015-11-13 04:24
poj
POJ 2524,
Ubiquitous
Religions
并查集 DescriptionThere are so many different religions in the world today that it is difficult to keep track of them all. You are interested in finding out how many different religions students in your
·
2015-11-13 01:05
poj
Ubiquitous
Religions
http://poj.org/problem?id=2524 这道题就是并查集。 1 #include<cstdio> 2 #include<cstring> 3 #include<iostream> 4 #define maxn 50010 5 using namespace std; 6 int a[maxn]; 7 i
·
2015-11-12 23:38
qui
poj----
Ubiquitous
Religions
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 20689
·
2015-11-12 12:54
poj
POJ 2524 并查集
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions
·
2015-11-11 13:26
poj
poj 2524:
Ubiquitous
Religions(并查集,入门题)
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions
·
2015-11-11 11:31
poj
POJ 2524
Ubiquitous
Religions(并查集)
题目链接 赤裸裸的并查集,搞不懂为什么POJ计划里,会用分治做。。 1 #include <stdio.h> 2 #include <string.h> 3 #define N 50001 4 int o[N]; 5 int find(int x) 6 { 7 int r,t; 8 r = x; 9 while
·
2015-11-11 10:11
poj
POJ 2524
Ubiquitous
Religions (并查集)
文章作者:ktyanny 文章来源:ktyanny 转载请注明,谢谢合作。 ktyanny:a的第二道并查集。第一题在 这里 题目描述: 世界上宗教何其多。假设你对自己学校的学生总共有多少种宗教信仰很感兴趣。学校有n个学生,但是你不能直接问学生的信仰,不然他会感到很不舒服的。有另外一个方法是问m对同学,是否信仰同一宗教。根据这些数据,相信聪明的
·
2015-11-08 12:27
poj
POJ 2524
Ubiquitous
Religions 【并查集】
解题思路:输入总人数 n,和m组数据;即和杭电畅通工程相类似,对这m组数据做合并操作后,求最后一共有多少块区域。 #include<stdio.h> int pre[50001]; int find(int root) { if(root!=pre[root]) pre[root]=find(pre[root]); return pre[root]; } v
·
2015-11-07 14:40
poj
分享我对领域驱动设计(DDD)的学习成果
领域通用语言(
Ubiquitous
Language) 4. 将领域模型转换为代码实现的最佳实践 5. 领域建模时思考问题的角度 6.
·
2015-11-07 11:28
学习
Ubiquitous
Religions(并查集)
Description There are so many different religions in the world today that it is difficult to keep track of them all. You are interested in finding out how many different religions students in your u
·
2015-11-07 11:26
并查集
OpenStack概念
OpenStack is a global collaboration ofdevelopers and cloud computing technologists producing the
ubiquitous
·
2015-11-07 11:37
openstack
TinyOS
BSD-licensed operating system designed for low-power wireless devices, such as those used in sensor networks,
ubiquitous
·
2015-11-05 08:48
OS
Ubiquitous
Religions--POJ 2524
1、解题思路:并查集。 2、注意事项:借用father[]、rank[]两个数组记录的小技巧。 3、实现方法: 1 #include < iostream > 2 #define M 50010 3 using namespace std;
·
2015-11-02 16:58
poj
POJ 2524 (简单并查集)
Ubiquitous
Religions
题意:有编号为1到n的学生,然后有m组调查,每组调查中有a和b,表示该两个学生有同样的宗教信仰,问最多有多少种不同的宗教信仰 简单并查集 1 //#define LOCAL 2 #include <iostream> 3 #include <cstdio> 4 #include <cstring> 5 using n
·
2015-11-02 11:52
poj
pku 2524
Ubiquitous
Religions
http://poj.org/problem?id=2524 题目分类是分治,我不知道怎么用分治。并查集1y.注意这里每个人最多有一个宗教信仰 View Code #include <iostream>#include <cmath>#include <cstdio>#include <cstring>#define maxn 5000
·
2015-11-01 14:56
pku
ASP.NET Web API与Rest web api(一)
HTTP is simple, flexible, and
ubiquitous
. Almost any platform that you can th
·
2015-11-01 12:21
asp.net
分享我对领域驱动设计(DDD)的学习成果
领域通用语言(
Ubiquitous
Language) 4. 将领域模型转换为代码实现的最佳实践 5. 领域建模时思考问题的角度 6.
·
2015-11-01 12:52
学习
DDD领域驱动设计基本理论知识总结
领域驱动设计之领域模型 为什么建立一个领域模型是重要的 领域通用语言(
UBIQUITOUS
LANGUAGE) 将领域模型转换为代码实现的最佳实践 领域建模时思考问题的角度 领域驱动设计的经典分层架构
·
2015-11-01 11:40
总结
pku2524-----
Ubiquitous
Religions(初次接触并查集)
方法一:time limited:对于合并操作要搜遍全部元素 Code //并查集 //方法一:用集合中最小元素标记集合。 //对于合并操作要搜遍全部元素。 #include<stdio.h> int set[50001],n,m,a,b,caseno=0; void init() { &n
·
2015-11-01 09:41
并查集
Home | eMine: Web Page Transcoding Based on Eye Tracking Project Page
Based on Eye Tracking Project Page The World Wide Web (web) has moved from the Desktop and now is
ubiquitous
·
2015-10-31 18:25
project
POJ 2524
Ubiquitous
Religions
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 17089
·
2015-10-31 15:52
poj
POJ 2524
Ubiquitous
Religions
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions
·
2015-10-31 11:34
poj
The 1st International Conference on Multimedia and
Ubiquitous
Engineering
will be the most comprehensive conference focused on the various aspects of advances in Multimedia and
Ubiquitous
·
2015-10-31 11:55
Engine
POJ 2524
Ubiquitous
Religions (最简单的并查集)
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions
·
2015-10-31 11:46
poj
poj2524
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 
·
2015-10-31 10:11
poj
POJ---2524
Ubiquitous
Religions[简单并查集]
Ubiquitous
Religions Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 17762
·
2015-10-31 10:23
poj
Ubiquitous
Religions(无处不在的宗教)
poj 2524 并查集基础题,但是由于刚开始不熟悉,还是错了好几次 题目大意:有学生学号1--n,给你一些学生之间的关系,即属于同一宗教的学生, 找出共有多少不同的宗教数 解决:就是一个并查集的最基础题目,写个并查集就过了 #include <stdio.h> #include <string.h> int num[50005]; int n,m;
·
2015-10-31 10:28
qui
POJ 2524
Ubiquitous
Religions (并差集)
http://acm.pku.edu.cn/JudgeOnline/problem?id=2524 #include <iostream>//对并差集的不熟悉 #include <cstdio> using namespace std; long p[50010],n,m,tmp,rel[50010];
·
2015-10-31 09:27
poj
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