Educational Codeforces Round 57 (Rated for Div. 2) ABCDEF题解
题目总链接:https://codeforces.com/contest/1096A.FindDivisible题意:给出l,r,在[l,r]里面找两个数x,y,使得y%x==0,保证有解。题解:直接输出l,2*l就好啦,但我还是写了个循环...代码如下:#includeusingnamespacestd;typedeflonglongll;constintN=10;intT;lll,r;intm