corner

亚像素经度在BeOS系统中的问题

Theproblemistwo-fold.AGGworkswithsub-pixelcoordinates.Thissimplymeansthatthecoordinate(5.0,4.0)referstothetopleft"corner"ofthepixelatindex
fengyuzaitu·2016-01-21 18:52

HDU 2438 Turn the corner

继续水3分。这题简直是个大写的数学题啊。首先如果w>x或者w>y那么显然不可能画一下汽车转角时的情况，发现车的右下角到左面那面墙的距离是个单峰函数，然后求这个函数的极值，极值小于y说明能过，不然就不能过。三分求极值#include #include #include #include usingnamespacestd; constdoubleeps=1e-6; constdoublepi=aco
nlj1999·2016-01-19 19:00

hdu-2438-Turn the corner(三分)

ProblemDescriptionMr.Westboughtanewcar!Soheistravellingaroundthecity.Onedayhecomestoaverticalcorner.Thestreetheiscurrentlyinhasawidthx,thestreethewantstoturntohasawidthy.Thecarhasalengthlandawidthd.Ca
qq_21120027·2016-01-07 21:00

Python: scikit-image binary descriptor

BRIEFbinarydescriptionalgorithmfromskimageimportdatafromskimageimporttransformastffromskimage.featureimport(match_descriptors,corner_peaks
Matrix_11·2015-12-20 13:28

Python: scikit-image binary descriptor

BRIEFbinarydescriptionalgorithmfromskimageimportdata fromskimageimporttransformastf fromskimage.featureimport(match_descriptors,corner_peaks
shinian1987·2015-12-20 13:00

SIFT特征提取分析

SIFT（Scale-invariant feature transform）是一种检測局部特征的算法，该算法通过求一幅图中的特征点（interest points,or corner points
·2015-11-13 22:10

screen to tmux: A Humble Quick-start Guide « My Humble Corner

screen to tmux: A Humble Quick-start Guide « My Humble Corner screen to tmux: A Humble
·2015-11-13 22:27

SIFT特征提取分析

SIFT（Scale-invariant feature transform）是一种检測局部特征的算法，该算法通过求一幅图中的特征点（interest points,or corner points
·2015-11-13 21:38

Android 圆角外边框

ListView控件； 2、main_vlist.xml是ListView中的每个Item控件布局， 3、在main_vlist.xml的最外层父元素的背景设为圆角边框awable/rounded_corner_border
·2015-11-13 20:08

[leetcode]Unique Paths

问题叙述性说明： A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram
·2015-11-13 17:38

leetcode------Unique Paths

标题： Unique Paths 通过率： 32.6%　　　　 难度： 中等 A robot is located at the top-left corner of a m
·2015-11-13 14:24

Leetcode | Unique Paths I & II

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
·2015-11-13 13:02

LeetCode | Unique Paths【摘】

A robot is located at the top-left corner of a m x n grid (marked ‘Start’ in the diagram below).
·2015-11-13 13:22

LeetCode-Unique Paths

Unique Paths A robot is located at the top-left corner of a m x n grid (marked '
·2015-11-13 12:50

Leetcode | Simplify Path

/c/", => "/c" Corner Cases:Did y
·2015-11-13 12:03

SIFT特征提取分析

SIFT（Scale-invariant feature transform）是一种检測局部特征的算法，该算法通过求一幅图中的特征点（interest points,or corner points
·2015-11-13 12:05

[LeetCode] Unique Paths

  A robot is located at the top-left corner of a m x n grid (marked 'Start'
·2015-11-13 09:22

css学习：斜角菜单的制作

制作斜角菜单就是利用边框的接角构造一个斜角，每一个菜单项的a元素，放置一个span元素，设置为corner类，实现斜角效果。
·2015-11-13 07:11

62. Unique Paths

题目： A robot is located at the top-left corner of a m x ngrid (marked 'Start' in the diagram
·2015-11-13 03:54

UVA 11880 Ball in a Rectangle（数学+平面几何）

Standard Input Output: Standard Output � There is a rectangle on the cartesian plane, with bottom-left corner
·2015-11-13 02:00

D3开发笔记

   caniuse.com Object Constancy http://bost.ocks.org/mike/constancy/ http://corner.squareup.com
·2015-11-13 01:23

[LeetCode#7]Reverse Integer

It is very easy at some aspects, however, it also needs a prudent mind to understand all corner cases
·2015-11-13 01:24

LeetCode: Unique Paths 解题报告

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the
·2015-11-13 00:40

【leetcode】Dungeon Game

Dungeon Game The demons had captured the princess (P) and imprisoned her in the bottom-right corner
·2015-11-13 00:56

【leetcode】Unique Paths

Unique Paths A robot is located at the top-left corner of a m x n grid (marked
·2015-11-13 00:39

css round corner div and transition

看stackoverflow上的圆角标签挺好看，自己动手试了下，用的属性是border-radius(即边框圆角半径，用px)；加上transition effect，代码如下： <!DOCTYPE html> <html> <head> <style> div { width:58px; border-style:solid;
·2015-11-13 00:35

leetcode_question_62 Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the
·2015-11-13 00:58

HDU 4467 Graph（图论+暴力）（2012 Asia Chengdu Regional Contest）

One day, when he was studying hard, GS appeared around the corner shyly and came up with a problem: 
·2015-11-13 00:49

LeetCode_Simplify Path

/c/", => "/c" Corner Cas
·2015-11-12 23:19

Harris 角点检测

一 、Motivation 对于做图像处理的人来说，Harris角点检测肯定听过，1988年发表的文章“A combined corner and edge detector”描述了这种角点检测方法
·2015-11-12 21:36

CCI_chapter 8 Recurision

8.1 水题 8.2 Imagine a robot sitting on the upper left hand corner of an NxN grid The robot can 
·2015-11-12 20:15

LeetCode_Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
·2015-11-12 20:01

给线k动画的思路。 这个对我没用不过，很重要

 sp = splineShape() addnewSpline sp addKnot sp 1 #corner #line [0,0,0] addKnot sp 1 #corner #
·2015-11-12 20:28

Reading papers_8(与图像特征点检测相关,ing...)

A combined corner and edge detector, Manchester, UK.
·2015-11-12 18:58

Android之实现iphone样式的圆角框的几种方法

一、可以借助shape，corner元素方法实现（背景）。 下面的circular_corner_dialog.xml文件定义了一个圆角矩形。
·2015-11-12 18:48

直线y=x

shp = splineShape() select shp spln = addNewSpline shpfor i = 1 to 1000 do ( addKnot shp spln  #corner
·2015-11-12 16:46

鼠标pos 视图的尺寸

The coordinates are in pixel values relative to the top-left corner of the screen&nbs
·2015-11-12 16:37

Collections > Collection Types > ObjectSet Values max 删除清除选择的路径

  <objectset>.max : Point3, read-only Returns maximum corner of bounding box.
·2015-11-12 16:26

Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the
·2015-11-12 16:41

杭电 2438 Turn the corner 解题报告

    解题报告：自己画个图，可知，在y>=max(w/sin(a)+l*cos(a)-x/tan(a))(0<=a<=90)时，汽车可以通过，否则不可通过。     对于这种函数，可以使用三分法，求最大值。笔者比较懒。。。直接暴力，代码如下： #include<iostream> #include<cmath&g
·2015-11-12 15:58

ie6bug----ie6默认的最小高度是设定字体的高度

.corner{ width:10px; height:10px; background:url(images/corner_opacity.png)
·2015-11-12 13:51

两条线中画终点

line02.center new_spline = splineShape () addNewSpline new_spline   addKnot new_spline 1 #corner
·2015-11-12 12:46

HDU 2438 Turn the corner【三分】

题目大意：给出汽车当前的街道宽度为x，要转弯进入的街道宽度为y,给出汽车的长度和宽度，为能否通过 解题思路：如果给我一道三分的题目，我还真的不知道往哪里去想。看到这个大牛的博客才知道思路是怎样的http://hi.baidu.com/novosbirsk/item/b52cd716a2068d463a176e07  车转弯的时候车有段与地面的夹角角度是从0度变化到90度的。也就是转
·2015-11-12 11:05

【LeetCode练习题】Unique Paths

Unique Paths A robot is located at the top-left corner of a m x n grid
·2015-11-12 11:10

Jquery div边框大全

网址 http://jquery.malsup.com/corner/     jQuery Corner是一款jQuery的插件，最初由Dave Methvin开发，但后在
·2015-11-12 10:01

Unique Paths

Dynamic Programming A robot is located at the top-left corner of a m x n grid
·2015-11-12 10:32

Android --- 图片的特效处理

Android --- 图片处理的方法 转换 -  drawable To  bitmap 缩放 -  Zoom 圆角 -  Round Corner
·2015-11-12 10:04

Find Peak Element

  For corner elements, we need to consider only one neighbor. For exa
·2015-11-11 19:21

Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the
·2015-11-11 18:34

jQuery DIV圆角插件之jquery.corner.js

jquery-1.2.6.js"></script> <script type="text/javascript" src="jquery.corner.js
·2015-11-11 17:25
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