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edges
关于UIScrollView的约束问题
scrollView addSubview:container];[container mas_makeConstraints:^(MASConstraintMaker *make) { make.
edges
.equalTo
zhao15127334470
·
2016-05-07 10:00
JAVA sort
目前知道Collections.sort();Arrays.sort();arrayList1.sort();等用法要自定义排序需要用Comparator比较麻烦还好有λ表达式Arrays.sort(
edges
YYecust
·
2016-05-05 22:00
HDU 5137 How Many Maos Does the Guanxi Worth
include usingnamespacestd; #definemaxn100 #defineINF1e9 #definemaxm1000 structEdge { intto,next,w; }
edges
qq_21057881
·
2016-05-02 21:00
Codeforces--246D--Colorful Graph(STL set)
64bitIOFormat: %I64d&%I64uSubmit StatusDescriptionYou'vegotanundirectedgraph,consistingof n verticesand m
edges
.Wewillconsiderthegraph'sverticesn
qq_29963431
·
2016-04-30 22:00
HDU 5606 tree(并查集的应用)
ProblemDescriptionThereisatree(thetreeisaconnectedgraphwhichcontainsnpointsandn−1
edges
),thepointsarelabeledfrom1ton
qq_32866009
·
2016-04-30 15:00
并查集
设置UIButton中的文字和图片,设置UILabel的文在显示不同颜色
UIEdgeInsets { CGFloat top, left, bottom, right; // specify amount to inset (positive) for each of the
edges
hbblzjy
·
2016-04-27 12:00
UILabel
UIButton
Codeforces Round #347 (Div. 2) D. Graph Coloring(最少需要选择多少个点,使得所有边的颜色相同)
D.GraphColoringtimelimitpertest1secondmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputYouaregivenanundirectedgraphthatconsistsof n verticesand m
edges
.Initially
acm_fighting
·
2016-04-26 20:00
dijkstra算法模板
2.注意为了存储整张图的完整信息,G[u]容器中存储的是与u相邻的边在
edges
容器中的下标位置。3
qq_29169749
·
2016-04-21 11:00
Code Forces Bear and Forgotten Tree 3 639B
B.BearandForgottenTree3timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingofnverticesandn - 1
edges
.Verticesarenumbe
Dacc123
·
2016-04-16 11:00
639B
Code-Force
CF 568 C 构造
C.BearandForgottenTree3timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesaren
zcj5027
·
2016-04-15 17:00
SGU 136 Erasing
Edges
(计算几何)
Description顺次给出一个n边形的n条边的中点坐标,问这个n边形是否存在,如果存在,顺次输出n个顶点的坐标,否则输出NOInput第一行为一整数n表示边数,之后n行每行两个数表示该条边的中点坐标(3 #include #include #include #include #include #include #include #include #include usingnamespaces
V5ZSQ
·
2016-04-15 11:00
FZU 2141 Sub-Bipartite Graph
DescriptionGivenasimpleundirectedgraphGwithnverticesandmedges,yourtaskistoselectasub-bipartitegraphofGwithatleastm/2
edges
.Inthemathematicalfieldofgraphtheory
jtjy568805874
·
2016-04-14 21:00
FZU
像素风图案缩放后变模糊(被消除锯齿)的解决办法
TestPage img { image-rendering:optimizeSpeed; image-rendering:-moz-crisp-
edges
;/*Firefox*/ image-rendering
yyf1990cs
·
2016-04-13 18:00
Codeforces--658C--Bear and Forgotten Tree 3(模拟&&技巧)(好题)
I64d&%I64uSubmit StatusDescriptionAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesarenumbe
qq_29963431
·
2016-04-10 11:00
VK Cup 2016 - Round 1 (Div. 2 Edition) C D
C.BearandForgottenTree3timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingofnverticesandn - 1
edges
.Verticesar
libin66
·
2016-04-06 23:00
GraphX源码解析(Graph构建过程)
1.构建图的方法从边的集合构建图(Graph.fromEdges)deffromEdges[VD:ClassTag,ED:ClassTag](
edges
:RDD[Edge[ED]], defaultValue
ZCF1002797280
·
2016-04-06 15:00
spark
GraphX
图构建
GraphX源码分析
Graph构建
【VK Cup 2016 - Round 1 (Div 2 Edition)C】【构造】Bear and Forgotten Tree 3 构造一棵树直径为d且点1的深度为h
BearandForgottenTree3timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesarenum
snowy_smile
·
2016-04-04 18:00
codeforces
构造
题库-CF
Codeforces 639B (构造)
C.BearandForgottenTree3timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesaren
morejarphone
·
2016-03-29 14:00
VK Cup 2016 - Round 1 B. Bear and Forgotten Tree 3
timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingofnverticesandn - 1
edges
.Verticesarenumbered1throughn.Limakisali
u014258433
·
2016-03-29 13:00
uva11090(二分spfa)
Input:standardinputOutput:standardoutput Youaregivenaweighteddirectedgraphwith n verticesand m
edges
.Eachcycleinthegraphhasaweight
martinue
·
2016-03-29 11:00
ACM
图
大二
VK Cup 2016 - Round 1 (Div. 2 Edition) C. Bear and Forgotten Tree 3 构造
www.codeforces.com/contest/658/problem/CDescriptionAtreeisaconnectedundirectedgraphconsistingofnverticesandn - 1
edges
.Verticesarenumbered1throughn.Limakisalittlepo
qscqesze
·
2016-03-29 09:00
codeforces 653E. Bear and Forgotten Tree 2 连通问题
E.BearandForgottenTree2timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesaren
FTQOOO
·
2016-03-28 19:00
缩点
联通块
Codeforces 653E (BFS set)
E.BearandForgottenTree2timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesaren
morejarphone
·
2016-03-22 23:00
IndiaHacks 2016 - Online Edition (Div. 1 + Div. 2) E. Bear and Forgotten Tree 2 bfs set 反图的生成树
www.codeforces.com/contest/653/problem/EDescriptionAtreeisaconnectedundirectedgraphconsistingofnverticesandn - 1
edges
.Verticesarenumbered1throughn.Limakisalittlepo
qscqesze
·
2016-03-21 15:00
[从头学数学] 第141节 勾股定理 小结与复习题
vartriangle=newTriangle(); vara=triangle.know2
edges
([200,300]); var
mwsister
·
2016-03-19 16:00
图论1E,cf405E
LittleChrisisparticipatinginagraphcuttingcontest.He'sapro.Thetimehascometotesthisskillstothefullest.Chrisisgivenasimpleundirectedconnectedgraphwith n vertices(numberedfrom1to n)and m
edges
.Theproblemi
yuanjunlai141
·
2016-03-19 10:00
蓝桥杯_算法训练_安慰奶牛(用Kruskal、Prim算法分别实现)
第j条双向道路连接了牧场Sj和Ej(1
edges
=newArrayList();//边集合 privatestaticArray
huangxiang360729
·
2016-03-14 19:00
算法
Prim
kruskal
邻接表(Java)
一、邻接表无线图无向图的邻接表结构如下所示:无向图的邻接表的代码实现:/* *邻接表无向图(已提供参数) *输入说明:vexs--顶点数组 *
edges
--边数组 *输出说明:邻接表(即每个顶点所连接的点
GongchuangSu
·
2016-03-11 22:00
[LeetCode] Graph Valid Tree 图验证树
eachedgeisapairofnodes),writeafunctiontocheckwhethertheseedgesmakeupavalidtree.Forexample:Given n=5 and
edges
Grandyang
·
2016-03-09 13:00
310. Minimum Height Trees
Stripoffthetreelayerbylayerfromoutside.importjava.lang.reflect.Array; publicclassSolution{ publicListfindMinHeightTrees(intn,int[][]
edges
新一代的天皇巨星
·
2016-03-06 07:00
CodeForces 639B Bear and Forgotten Tree 3(水题)
timelimitpertest2secondsmemorylimitpertest256megabytesinputstandardinputoutputstandardoutputAtreeisaconnectedundirectedgraphconsistingof n verticesand n - 1
edges
.Verticesarenumbered
imwutianqi
·
2016-03-05 16:00
Operations on
edges
in polyhedron
http://doc.cgal.org/latest/Polyhedron/classCGAL_1_1Polyhedron__3_1_1Vertex.htmljudgewhetherahalfedgeisborderboolis_border(halfedge_descriptorconst&aEdge) const{returnface(aEdge,mSurface)==boost::graph
seamanj
·
2016-03-04 23:00
[置顶] 文献笔记:《Fitting a 3D Morphable Model to
Edges
: A Comparison Between Hard and Soft Correspondences》
这也是最近读的arXiv文献,关于基于单幅人脸图像进行三维重构的,注意是单幅人脸图像,而不是两幅或者多幅,单凭这一点就很吸引人,因为其难度很大,之前的算法包括自己实现过的算法,效果都一塌糊涂,那本文介绍的算法有何过人之处?我们可以先看看它的效果图。图1.三维重构效果图,第一行:大姿态,第二行:正面照,第三行,基于第一行恢复的正面照 有没有眼前一亮的感觉?第三行和第二行相比,除了不可避
wsj998689aa
·
2016-02-27 13:00
人脸三维重构
关于图论的基础概念
图(graph)是由非空有限集合V和集合E组成,记为G=(V,E);其中V中的元素称为顶点(vertices),E中的元素称为边(
edges
);这是相当直观的,易于理解;但是需要注意的是图论的术语在使用上不统一
LeeHolmes
·
2016-02-20 22:00
图论
HDU 5631 Rikka with Graph
Rikkaispooratmath.Yutaisworryingaboutthissituation,sohegivesRikkasomemathtaskstopractice.Thereisoneofthem:Yutahasanon-directgraphwithnverticesandn+1
edges
.Rikkacanchoosesomeo
jtjy568805874
·
2016-02-20 21:00
HDU
leetcode - Minimum Height Trees
intid;unordered_setnext;Node(inta):id(a){}};classSolution{public:vectorfindMinHeightTrees(intn,vector>&
edges
bupt8846
·
2016-02-15 22:44
leetcode
最大流dinic 模版 (训练指南)
vectorG[maxn]; boolvis[maxn]; intd[maxn]; intcur[maxn]; voidinit(intn) { REP(i,1,n)G[i].clear();
edges
.clea
__560
·
2016-02-15 16:00
12.1、PageRank实例
gclass(g)[1]"igraph">gIGRAPHD---1026--Erdosrenyi(gnp)graph+attr:name(g/c),type(g/c),loops(g/l),p(g/n)+
edges
qq_16365849
·
2016-02-12 09:00
机器学习
pagerank
十五、polygon API
HowpolygonsarehandledinternallyThefivebasicpolygonalAPIclassesConstructionHistoryandTweakspolyModifierCmdexamplesplitUVCmdexamplePolyexporterplug-ins用来存储polygon(faces,
edges
Rambo.Wang
·
2016-02-11 14:00
dijkstra模版
booldone[maxn]; intd[maxn]; intp[maxn]; voidinit(intn) { this->n=n; REP(i,1,n)G[i].clear();
edges
.clear
__560
·
2016-02-10 20:00
HDU 5606 tree
ProblemDescriptionThereisatree(thetreeisaconnectedgraphwhichcontains nn pointsand n-1n−1
edges
),thepointsarelabeledfrom1to
jtjy568805874
·
2016-02-02 18:00
HDU
UIScrollview 与 Autolayout 的那点事
new];[scrollViewaddSubview:container];[containermas_makeConstraints:^(MASConstraintMaker*make){make.
edges
.equalT
rosee
·
2016-01-29 02:00
hdu 5606 tree(并查集)
ProblemDescriptionThereisatree(thetreeisaconnectedgraphwhichcontains n pointsand n−1
edges
),thepointsarelabeledfrom1to
UniqueColor
·
2016-01-28 00:00
【最大流FF模板】HDU1532&POJ1273
include 7#include 8usingnamespacestd; 9constintMAXN=1100; 10constintINF=0x7fffffff; 11intn,m;//n:
edges
GufuVelvirki
·
2016-01-23 14:00
iOS开发:Block作为返回值时的使用
作为返回值使用时的情况,先贴一小段热门第三方框架Masonry的官方samplecode:[view1mas_makeConstraints:^(MASConstraintMaker*make){ make.
edges
.equalTo
夏鲁鲁
·
2016-01-22 21:00
Problem with blending
edges
of connected shapes
提供展示代码: agg::rendering_buffer&rbuf=rbuf_window(); agg::pixfmt_bgr24pixf(rbuf); typedefagg::renderer_baserenderer_base_type; renderer_base_typerenb(pixf); typedefagg::renderer_scanline_a
fengyuzaitu
·
2016-01-17 17:58
agg
绘制较宽轮廓和尖锐边缘,AGG渲染问题
last weeks and I have come up with following problem: when painting wide outlines of paths with sharp
edges
fengyuzaitu
·
2016-01-17 09:46
agg
stroke
边缘
unsupported format or combination of ···解决方法
如下图: 出错原因在cvCanny函数cvCanny函数用来进行边缘检测,函数原型如下:CVAPI(void) cvCanny(constCvArr*image,CvArr*
edges
,doublethreshold1
我叮叮咚咚
·
2016-01-16 16:00
无向图相关算法基础
之所以要研究图,是因为图在生活中应用比较广泛:无向图图是若干个顶点(Vertices)和边(
Edges
)相互连接组成的。边仅由两个顶点连接,并且没有方向的图称为无向图。在
lpx15312
·
2016-01-11 13:00
图是否是树
给出 n 个节点,标号分别从 0 到 n-1 并且给出一个 无向 边的列表(给出每条边的两个顶点),写一个函数去判断这张`无向`图是否是一棵树样例给出n=5 并且
edges
=[[0,1],[0,2],
brucehb
·
2016-01-09 00:00
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