杭电 hdu 1253 胜利大逃亡

三维广搜，因为数据量很大，所以要用scanf 和 printf，否则注定要超时。但是也因为数据量很大的，所以数据并不刁钻，没有多少边界数据，所以很多剪枝用了都没有效果。直接用广搜的模板修改即可通过了。

/* THE ROGRAM IS MADE BY PYY */ /*----------------------------------------------------------------------------// URL : http://poj.org/problem?id=2243 Name : Knight Moves Date : Tuesday, April 20, 2010 Time Stage : 0:14 Result: 3846143 2011-04-20 22:12:10 Accepted 1253 952MS 1588K 4083 B C++ pyy Test Data: //----------------------------------------------------------------------------*/ #include <iostream> #include <queue> #include <string.h> #include <stdio.h> using namespace std; struct node { int x, y, z; }; const int maxSize = 55, directions[][3] = { {1, 0, 0}, {0, 1, 0}, {0, 0, 1}, {-1, 0, 0}, {0, -1, 0}, {0, 0, -1} }; int blocks, rows, columns, backTime; int map[maxSize][maxSize][maxSize], path[maxSize][maxSize][maxSize]; void out( node a ) { printf("%d, %d, %d/n", a.x, a.y, a.z ); } void bfs() { // the door is wall if( map[blocks-1][rows-1][columns-1] ) { path[blocks-1][rows-1][columns-1] = -1; return ; } // start point is door if( blocks * rows * columns == 1 && !map[0][0][0] ) { path[blocks-1][rows-1][columns-1] = 0; return ; } memset( path, 0, sizeof( path ) ); // mark the start point path[0][0][0] = 1; int i, j, k, m; queue<node> q; node n; n.x = 0; n.y = 0; n.z = 0; q.push( n ); while( !q.empty() ) { n = q.front(); q.pop(); for( i = 0; i < 6; i++ ) { node tmp; tmp.x = n.x + directions[i][0]; tmp.y = n.y + directions[i][1]; tmp.z = n.z + directions[i][2]; // border check if( tmp.x < 0 || tmp.y < 0 || tmp.z < 0 || blocks <= tmp.x || rows <= tmp.y || columns <= tmp.z ) continue; // already visited if( map[tmp.x][tmp.y][tmp.z] || path[tmp.x][tmp.y][tmp.z] ) continue; // visited it path[tmp.x][tmp.y][tmp.z] = path[n.x][n.y][n.z] + 1; if( path[tmp.x][tmp.y][tmp.z] > backTime ) { path[blocks-1][rows-1][columns-1] = -1; return ; } q.push( tmp ); // hit terminus if( tmp.x == blocks - 1 && tmp.y == rows - 1 && tmp.z == columns - 1 ) { --path[blocks-1][rows-1][columns-1]; return ; } } } path[blocks-1][rows-1][columns-1] = -1; } int main() { int i, j, k, tcase; while( cin >> tcase ) { while( tcase-- ) { cin >> blocks >> rows >> columns >> backTime; for( i = 0; i < blocks; i++ ) for( j = 0; j < rows; j++ ) for( k = 0; k < columns; k++ ) scanf("%d", &map[i][j][k]); bfs(); printf("%d/n", path[blocks-1][rows-1][columns-1]); } } return 0; }