PAT甲级 1023. Have Fun with Numbers (20)

1023. Have Fun with Numbers (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a different permutation. Check to see the result if we double it again!

Now you are suppose to check if there are more numbers with this property. That is, double a given number with k digits, you are to tell if the resulting number consists of only a permutation of the digits in the original number.

Input Specification:

Each input file contains one test case. Each case contains one positive integer with no more than 20 digits.

Output Specification:

For each test case, first print in a line "Yes" if doubling the input number gives a number that consists of only a permutation of the digits in the original number, or "No" if not. Then in the next line, print the doubled number.

Sample Input:

1234567899

Sample Output:

Yes
2469135798

一个由0到9排列组合的数判断它乘以2以后是不是同样由这些数排列组合得到

#include 
#include 
#include 
using namespace std;
int cnt1[10] = { 0 }, cnt2[10] = {0};

int main(){
    string s;
    cin >> s;
    string s2 = s;
    for (int i = 0; i < s.size(); i++){
        cnt1[s[i] - '0']++;
    }
    int carry = 0;
    for (int i = s.size() - 1; i >= 0; i--){
        s2[i] = ((s[i] - '0') * 2 + carry )% 10 + '0';
        carry = ((s[i] - '0') * 2 + carry) / 10;
    }
    if (carry){
        char c = carry + '0';
        cout << "No\n" <