提高查询效率

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原来的:

 List conventions = test2Boy.getConventions();
            for (Convention convention : conventions) {
                //因为在html中\n不会换行,所以要把\n转化为br
                convention.setAnswer(ConventionUtil.convertBr(convention.getAnswer()));
                VoteLog voteLogTmp=this.voteLogDao.get( "user.id", user2.getId(),"convention.id",convention.getId());
                if(null!=voteLogTmp){
                    convention.setHasStar(true);
                }
            }

 conventions 有多少个元素,就得执行多少次sql语句

优化:

 List conventions = test2Boy.getConventions();
            int size=conventions.size();
            Object[]objects=new Object[size];
            for (int i=0;i 
  

 

执行的sql语句为:

/* criteria query */ select
        this_.id as id1_8_2_,
        this_.conventionId as conventi4_8_2_,
        this_.status as status2_8_2_,
        this_.userId as userId5_8_2_,
        this_.vote_time as vote3_8_2_,
        convention2_.id as id1_2_0_,
        convention2_.answer as answer2_2_0_,
        convention2_.pic as pic3_2_0_,
        convention2_.stars as stars4_2_0_,
        convention2_.status as status5_2_0_,
        convention2_.update_time as update6_2_0_,
        user3_.id as id1_7_1_,
        user3_.email as email2_7_1_,
        user3_.level as level3_7_1_,
        user3_.nickname as nickname4_7_1_,
        user3_.password as password5_7_1_,
        user3_.potrait as potrait6_7_1_,
        user3_.username as username7_7_1_ 
    from
        t_vote_log this_ 
    left outer join
        t_convention convention2_ 
            on this_.conventionId=convention2_.id 
    left outer join
        t_user user3_ 
            on this_.userId=user3_.id 
    where
        this_.userId=? 
        and this_.conventionId in (
            ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?
        )

 

 

 

 

 

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