PAT甲级最短路
主要算法：dijkstra 求最短最长路、dfs图论搜索。
1018，dijkstra记录路径 + dfs搜索路径最值
25分，错误点暂时找不出。。
如果只用dijkstra没法做，只能得20分
#include
using namespace std;
const int inf = 0x3f3f3f3f;
const int maxn = 510;
int cmax,n,ter,m;
int caps[maxn];
int g[maxn][maxn];
int vis[maxn];
vector pre[maxn];
int dist[maxn];
int half;
vector paths;
vector temp;
int minsend = inf;
int mintake = inf;
//dfs
void dfs(int x){
temp.push_back(x);
if(x == 0){
int need = 0;
int take = 0;
for(int i=0;i 0){
int d = caps[temp[i]] - half;
if(need >= d) need -= d;
else{
need = 0;
take += (d - need);
}
}else{
need += (half - caps[temp[i]]);
}
}
if(need < minsend){
minsend = need;
mintake = take;
paths = temp;
}else if(need == minsend){
if(mintake > take){
mintake = take;
paths = temp;
}
}
temp.pop_back();
return;
}
for(int i=0;i>cmax>>n>>ter>>m;
half = cmax/2;
caps[0] = 0;
for(int i=1;i<=n;i++) cin>>caps[i];
for(int i=1;i<=m;i++){
int u,v,w;
cin>>u>>v>>w;
g[u][v] = w;
g[v][u] = w;
}
dijkstra();
dfs(ter);
cout<0;i--){
cout<";
}
cout< 1030，多边权，多条更新
#include
using namespace std;
/*
dijkstra:双边权
*/
const int inf = 0x3f3f3f3f;
const int maxn = 510;
int n,m,s,d;
int dist[maxn];
int path[maxn];
int cost[maxn];
int vis[maxn];
struct edge{
int v,w,c;
edge(int vv,int ww,int cc){
v = vv;
w = ww;
c = cc;
}
};
vector paths;
vector g[maxn];
void dijkstra(int ss){
memset(vis,0,sizeof(vis));
memset(dist,inf,sizeof(dist));
memset(cost,inf,sizeof(cost));
dist[ss] = 0;
cost[ss] = 0;
path[ss] = -1;
for(int i=0;i cost[v] + g[v][j].c){
path[x] = v;
cost[x] = cost[v] + g[v][j].c;
}
}
}
}
}
int main(){
cin>>n>>m>>s>>d;
for(int i=1;i<=m;i++){
int u,v,w,c;
cin>>u>>v>>w>>c;
g[u].push_back(edge(v,w,c));
g[v].push_back(edge(u,w,c));
}
dijkstra(s);
int cur = d;
while(cur != -1){
paths.push_back(cur);
cur = path[cur];
}
for(int i=paths.size()-1;i>=0;i--){
cout< 1087，记录所有路径，dfs搜索路径最值
#include
using namespace std;
/*
map映射:string <-> cityId Name <-> Int
dijkstra:找出最短路的长度 以及所有最短路径(存入到pre容器中)
dfs:统计最短路的数量 从终点触发在出口判断更新所需的权值
*/
const int inf = 0x3f3f3f3f;
const int maxn = 210;
map mp;
map mp2;
int n,k;
string start;
int haps[maxn];
int g[maxn][maxn];
int nums;
int vis[maxn];
int dist[maxn];
int ter = 0;
vector pre[maxn];
vector temp,path;
int maxhap = 0;
double maxave = 0;
void dfs(int x){
temp.push_back(x);
if(x == n){
int curhap = 0;
double curave = 0;
for(int i=temp.size()-1;i>=0;i--){
curhap += haps[temp[i]];
}
if(temp.size() == 1){
curave = 0;
}else{
curave = curhap*1.0/(temp.size()-1);
}
if(maxhap < curhap){
maxhap = curhap;
maxave = curave;
path = temp;
}else if(maxhap == curhap){
if(maxave < curave){
maxave = curave;
path = temp;
}
}
nums++;
temp.pop_back();
return;
}
for(int i=0;i dist[v] + g[v][j]){
dist[j] = dist[v] + g[v][j];
pre[j].clear();
pre[j].push_back(v);
}else if(dist[j] == dist[v] + g[v][j]){
pre[j].push_back(v);
}
}
}
}
}
int main(){
memset(g,inf,sizeof(g));
cin>>n>>k>>start;
for(int i=1;i<=n-1;i++){
string city;
int hap;
cin>>city>>hap;
mp[city] = i;
mp2[i] = city;
haps[i] = hap;
}
mp[start] = n;
mp2[n] = start;
haps[n] = 0;
for(int i=1;i<=k;i++){
string c1,c2;
int cost;
cin>>c1>>c2>>cost;
int u = mp[c1];
int v = mp[c2];
g[u][v] = cost;
g[v][u] = cost;
}
ter = mp["ROM"];
dijkstra(n);
dfs(ter);
cout<0;i--){
cout<<"->"<ROM"< 1111，多边权、记录路径、多条件更新
#include
using namespace std;
/*
30分
*/
const int inf = 0x3f3f3f3f;
const int maxn = 510;
int source,ter;
int n,m;
int vis1[maxn];
int vis2[maxn];
struct edge{
int v;
int length;
int time;
edge(int vv,int len,int ti){
v = vv;
length = len;
time = ti;
}
};
vector g[maxn];
int dist1[maxn];
int time1[maxn];
int time2[maxn];
int path1[maxn];
int path2[maxn];
int nums[maxn];
vector ans1;
vector ans2;
void dijkstra1(){
memset(vis1,0,sizeof(vis1));
memset(dist1,inf,sizeof(dist1));
memset(time1,inf,sizeof(time1));
dist1[source] = 0;
time1[source] = 0;
path1[source] = -1;
for(int i=0;i dist1[v] + g[v][j].length){
time1[u] = time1[v] + g[v][j].time;
dist1[u] = dist1[v] + g[v][j].length;
path1[u] = v;
}else if(dist1[u] == dist1[v] + g[v][j].length && time1[u] > time1[v] + g[v][j].time){
time1[u] = time1[v] + g[v][j].time;
path1[u] = v;
}
}
}
}
}
void dijkstra2(){
memset(vis2,0,sizeof(vis2));
memset(nums,inf,sizeof(nums));
memset(time2,inf,sizeof(time2));
nums[source] = 1;
time2[source] = 0;
path2[source] = -1;
for(int i=0;i time2[v] + g[v][j].time){
time2[u] = time2[v] + g[v][j].time;
nums[u] = nums[v] + 1;
path2[u] = v;
}else if(time2[u] == time2[v] + g[v][j].time){
if(nums[u] >= nums[v] + 1){
path2[u] = v;
nums[u] = nums[v] + 1;
}
}
}
}
}
}
bool identical(){
int cur = ter;
while(cur != -1){
ans1.push_back(cur);
cur = path1[cur];
}
cur = ter;
while(cur != -1){
ans2.push_back(cur);
cur = path2[cur];
}
reverse(ans1.begin(),ans1.end());
reverse(ans2.begin(),ans2.end());
if(ans1.size() != ans2.size()) return false;
for(int i=0;i>n>>m;
for(int i=1;i<=m;i++){
int v1,v2,one,length,time;
cin>>v1>>v2>>one>>length>>time;
if(one == 0){
g[v1].push_back(edge(v2,length,time));
g[v2].push_back(edge(v1,length,time));
}else{
g[v1].push_back(edge(v2,length,time));
}
}
cin>>source>>ter;
dijkstra1();
dijkstra2();
if(identical()){
printf("Distance = %d; Time = %d: %d",dist1[ter],time2[ter],source);
for(int i=1;i %d",ans1[i]);
}
printf("\n");
}else{
printf("Distance = %d: %d",dist1[ter],source);
for(int i=1;i %d",ans1[i]);
}
printf("\n");
printf("Time = %d: %d",time2[ter],source);
for(int i=1;i %d",ans2[i]);
}
printf("\n");
}
return 0;
}
/*
4 4
0 1 1 1 2
0 2 1 2 1
1 3 1 2 2
2 3 1 1 1
0 3
*/