关于获取iOS设备唯一标识符笔记

在iOS的开发过程中，我们常常会遇到获取设备的UUID，IDFV，IDFA，MAC地址等一系列的设备标识符。

什么是设备的UUID?更详细的介绍可以参考www.cocoachina.com/industry/20130422/6040.html

代码如下：

• 获取广告标示符（IDFA-identifierForIdentifier）

导入 #import < AdSupport/ASIdentifierManager.h >

+(NSString *)dy_getDeviceIDFA{

ASIdentifierManager *asIM = [[ASIdentifierManager alloc] init];

NSString *idfaStr = [asIM.advertisingIdentifier UUIDString];

return idfaStr;

}

• 获取Vindor标示符 (IDFV-identifierForVendor)

+(NSString *)dy_getDeviceIDFV{

NSString* idfvStr = [[UIDevice currentDevice] identifierForVendor].UUIDString;

return idfvStr;

}

Git上的erica的UIDevice扩展文件，以前可用但由于IOKit framework没有公开，所以也无法使用。就算手动导入，依旧无法使用，看来获取IMEI要失败了,同时失败的还有IMSI。不过还存在另外一种可能，Stack Overflow上有人提供采用com.apple.coretelephony.Identity.get entitlement方法，but device must be jailbroken；在此附上链接，供大家参考：http://stackoverflow.com/questions/16667988/how-to-get-imei-on-iphone-5/16677043#16677043

• 获取MAC地址

include 

include 

include 

include 

+(NSString*)dy_getDeviceMAC{

int mib[6];

size_t len;

char *buf;

unsigned char *ptr;

struct if_msghdr *ifm;

struct sockaddr_dl *sdl;

mib[0] = CTL_NET;

mib[1] = AF_ROUTE;

mib[2] = 0;

mib[3] = AF_LINK;

mib[4] = NET_RT_IFLIST;

if ((mib[5] = if_nametoindex(“en0”)) == 0) {

printf(“Error: if_nametoindex error\n”);

return NULL;

}

if (sysctl(mib, 6, NULL, &len, NULL, 0) < 0) {

printf(“Error: sysctl, take 1\n”);

return NULL;

}

if ((buf = malloc(len)) == NULL) {

printf(“Could not allocate memory. error!\n”);

return NULL;

}

if (sysctl(mib, 6, buf, &len, NULL, 0) < 0) {

printf(“Error: sysctl, take 2”);

free(buf);

return NULL;

}

ifm = (struct if_msghdr *)buf;

sdl = (struct sockaddr_dl *)(ifm + 1);

ptr = (unsigned char *)LLADDR(sdl);

NSString macStr = [NSString stringWithFormat:@”%02X:%02X:%02X:%02X:%02X:%02X”,ptr, *(ptr+1), *(ptr+2), *(ptr+3), *(ptr+4), *(ptr+5)];

free(buf);

return macStr;

}

• 获取UUID

+(NSString*)dy_getDeviceUUID{

CFUUIDRef uuid = CFUUIDCreate(NULL);

assert(uuid != NULL);

CFStringRef uuidStr = CFUUIDCreateString(NULL, uuid);

return (__bridge NSString *)(uuidStr);

}

UDID是肯定要被苹果拒绝的,Stack Overflow提供了另外一种方法，越狱可尝试：http://stackoverflow.com/questions/27602368/how-to-get-serial-number-of-a-device-using-iokit-in-ios8-as-ioplatformserialnumb/27686125#27686125