Codeforces Round #614 (Div. 2)C NEKO's Maze Game

题目

NEKO#ΦωΦ has just got a new maze game on her PC!

The game's main puzzle is a maze, in the forms of a 2×n rectangle grid. NEKO's task is to lead a Nekomimi girl from cell (1,1) to the gate at (2,n) and escape the maze. The girl can only move between cells sharing a common side.

However, at some moments during the game, some cells may change their state: either from normal ground to lava (which forbids movement into that cell), or vice versa (which makes that cell passable again). Initially all cells are of the ground type.

After hours of streaming, NEKO finally figured out there are only qq such moments: the ii -th moment toggles the state of cell (ri,ci) (either from ground to lava or vice versa).

Knowing this, NEKO wonders, after each of the qq moments, whether it is still possible to move from cell (1,1) to cell (2,n) without going through any lava cells.

Although NEKO is a great streamer and gamer, she still can't get through quizzes and problems requiring large amount of Brain Power. Can you help her?

Input

The first line contains integers n , q (2≤n≤1e5 , 1≤q≤1e5 ).

The ii -th of qq following lines contains two integers riri , cici (1≤ri≤2, 1≤ci≤n), denoting the coordinates of the cell to be flipped at the ii -th moment.

It is guaranteed that cells (1,1) and (2,n) never appear in the query list.

Output

For each moment, if it is possible to travel from cell (1,1) to cell (2,n) , print "Yes", otherwise print "No". There should be exactly qq answers, one after every update.

You can print the words in any case (either lowercase, uppercase or mixed).

Example

Input

Copy

5 5 2 3 1 4 2 4 2 3 1 4 Output

Copy

Yes No No No Yes Note

We'll crack down the example test here:

After the first query, the girl still able to reach the goal. One of the shortest path ways should be: (1,1)→(1,2)→(1,3)→(1,4)→(1,5)→(2,5)(1,1)→(1,2)→(1,3)→(1,4)→(1,5)→(2,5) . After the second query, it's impossible to move to the goal, since the farthest cell she could reach is (1,3)(1,3) . After the fourth query, the (2,3)(2,3) is not blocked, but now all the 44 -th column is blocked, so she still can't reach the goal. After the fifth query, the column barrier has been lifted, thus she can go to the final goal again.

大致题意

题意：给定一个2*n的空间，每次翻转一个空间，（整个空间初始都是可以通过的，翻转一次即不可通过，两次即可以通过）每当进行一次翻转，判断此时是否可以从空间（1，1）到达空间（2，n）。

注意

这道题因为只有两行，所以当翻转其中一个空间之后，我们只需判断这个空间位置的不同行同列和其相邻位置是否可以通过即可

最后看一下代码

 

#include 
using namespace std;
const int maxn = 1e5 + 10;
int vis[2][maxn];
int main(){
    ios::sync_with_stdio(0);
    int n,q,s,t,sum=0;
    cin>>n>>q;
    while (q--){
        cin>>s>>t;
        s--;
        vis[s][t]^=1;
        
        if (vis[s][t]==1){//必须分开进行判断，才能保证之前的翻转造成的不通路在翻转成可通过之后形成通路。
            if (vis[s^1][t+1]==1)
                sum++;
                if(vis[s^1][t]==1)
                sum++;
                if(vis[s^1][t-1]==1)
                sum++;
        }
        else{
            if (vis[s^1][t+1]==1)
                sum--;
                if(vis[s^1][t]==1)
                sum--;
                if(vis[s^1][t-1]==1)
                sum--;
            
        }
        if (sum== 0)
            cout << "Yes"<<endl;
        else
            cout << "No"<<endl;
    }
    return 0;
}