LeetCode 3Sum Closest C++

#include 
#include 
#include
#include 
using namespace std;

/************************************************************************/
/* 
    Problem:
        Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

        For example, given array S = {-1 2 1 -4}, and target = 1.

        The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

    Author  :   [email protected]

    DateTime:   2017年8月2日 18:39:17

*/
/************************************************************************/
class Solution {
public:
    int threeSumClosest(vector<int>& nums, int target)
    {

        sort(nums.begin(), nums.end());
        //Blind Dick, write a value, and then gradually contrast
        int value = nums[0] + nums[1] + nums[2];
        int diff = abs(target - value);
        for (int i =0;i2;i++)
        {
            int left = i + 1;
            int right = nums.size()-1;
            while (left < right)
            {
                int  temp = nums[i] + nums[left] + nums[right];
                //对比差值
                int newdiff = abs(target - temp);
                //差价较小//更新 返回值 、、
                if (newdiff < diff)
                {
                    diff = newdiff;
                    value = temp;
                }
                //because  sort   so :temp < target  ++ left   otherwise  --ritht
                if (temp < target)
                {
                    ++left;
                }
                else
                {
                    --right;
                }

            }
        }
        return value;

    }
};
void main()
{

    std::vector<int> arr = {1,1,1,0 };

    Solution s1;

    std::cout<100);

    std::cout<<""<"pause");

}