剑指offer---复杂链表复制

剑指offer面试题---复杂链表复制

分析此题：1.首先要将链表的每一个节点复制一份，连在被复制节点后面。

                   2.将对应的指向关系也对应复制。

                   3.分离原链表、复制链表。

代码实现：

struct ComplexListNode
{
	int _data;
	ComplexListNode* _next;
	ComplexListNode* _sibling;
};

1.将链表的每一个节点复制一份，连在被复制节点后面。

void CloneNode(ComplexListNode*pHead)
{
	ComplexListNode*pNode = pHead;
	while (pNode != NULL)
	{
		ComplexListNode*pClone = new ComplexListNode();
		pClone->_data = pNode->_data;
		pClone->_next = pNode->_next;
		pClone->_sibling = NULL;

		pNode->_next = pClone;
		pNode = pClone->_next;
	}
}

2.将对应的指向关系也对应复制

void ConnectSiblingNode(ComplexListNode*pHead)
{
	ComplexListNode*pNode = pHead;
	while (pNode != NULL)
	{
		ComplexListNode*pClone = pNode->_next;
		if (pNode->_sibling != NULL)
		{
			pClone->_sibling = pNode->_sibling->_next;
		}
	}
}

3.分离原链表、复制链表

ComplexListNode* ReconnectNode(ComplexListNode*pHead)
{
	ComplexListNode*pNode = pHead;
	ComplexListNode*pCloneHead = NULL;
	ComplexListNode*pCloneNode = NULL;
	if (pNode!=NULL)
	{
		pCloneHead = pCloneNode = pNode->_next;
		pNode->_next = pCloneNode->_next;
		pNode = pNode->_next;
	}
	while (pNode != NULL)
	{
		pCloneNode->_next = pNode->_next;
		pCloneNode = pCloneNode->_next;
		pNode->_next = pCloneNode->_next;
		pNode = pNode->_next;
	}
	return pCloneHead;
}
ComplexListNode*Clone(ComplexListNode*pHead)
{
	CloneNode(pHead);
	ConnectSiblingNode(pHead);
	return ReconnectNode(pHead);
}