抓瞎: 穷尽和求余匹配

python

# -.- coding:utf-8 -.-
# 遍历1到100
# 如果数字能被3整除就打印Fizz,
# 如果数字能被5整除就打印Buzz,
# 如果数字能同时被3和5整除就打印FizzBuzz,
# 剩下的就打印数字本身.
from __future__ import print_function


def main():
    for i in range(1, 101):
        fz = (i % 3, i % 5)
        if fz == (0, 0):
            print("FizzBuzz")
        elif fz[0] == 0:
            print("Fizz")
        elif fz[1] == 0:
            print("Buzz")
        else:
            print(i)


if __name__ == '__main__':
main()

rust

// 遍历1到100
// 如果数字能被3整除就打印Fizz,
// 如果数字能被5整除就打印Buzz,
// 如果数字能同时被3和5整除就打印FizzBuzz,
// 剩下的就打印数字本身.

fn main() {
    for i in 1..101 {
        match (i % 3, i %5) {
            (0, 0) => println!("FizzBuzz"),
            (0, _) => println!("Fizz"),
            (_, 0) => println!("Buzz"),
            _ => println!("{}", i)
        }
    }
}

输出

1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
Buzz