HDOJ 5014 Number Sequence

找规律

Number Sequence

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 303    Accepted Submission(s): 149
Special Judge

Problem Description

There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:

● a _i ∈ [0,n] 
● a _i ≠ a _j( i ≠ j )

For sequence a and sequence b, the integrating degree t is defined as follows(“⊕” denotes exclusive or):

t = (a ₀ ⊕ b ₀) + (a ₁ ⊕ b ₁) +···+ (a _n ⊕ b _n)

(sequence B should also satisfy the rules described above)

Now give you a number n and the sequence a. You should calculate the maximum integrating degree t and print the sequence b.

 

Input

There are multiple test cases. Please process till EOF. 

For each case, the first line contains an integer n(1 ≤ n ≤ 10 ⁵), The second line contains a ₀,a ₁,a ₂,...,a _n.

 

Output

For each case, output two lines.The first line contains the maximum integrating degree t. The second line contains n+1 integers b ₀,b ₁,b ₂,...,b _n. There is exactly one space between b _i and b _i+1 (0 ≤ i ≤ n - 1). Don’t ouput any spaces after b _n.

 

Sample Input

4 2 0 1 4 3

 

Sample Output

20 1 0 2 3 4

 

Source

2014 ACM/ICPC Asia Regional Xi'an Online

 

#include 
#include 
#include 
#include 
#include 

using namespace std;

int n,a[100100],sig[100100];
long long int ans;

int wei(int x)
{
    if(x==0) return 0;
    return log(x*1.)/log(2.0);
}

int main()
{
    while(scanf("%d",&n)!=EOF)
    {
        ans=0;
        memset(sig,-1,sizeof(sig));
        for(int i=n;i>=0;i--) 
        {
            if(n%2==0&&i==0) 
            {
                sig[0]=0;
                continue;
            }
            if(sig[i]!=-1)
            {
                ans+=i^sig[i];
                continue;
            }
            int w=wei(i);    
            w++;
            int fan=((1<