欧拉计划6 学习笔记 matlab 求：前100个自然数的平方和和和的差

Problem 6

The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

求：求前100个自然数的平方和和的差

思路

1. 求100个自然数和的平方 (1 + 2 + … + 100)^2
2. 求100个自然数平方的和 1^2 + 2^2 + … + 100^2
3. 相减

代码

%% 6 平方和-（和）的平方
suma=0;
sumb=0;
for i=1:1:100;
    i=i*i;
    suma=suma+i;
    i=i+1;   
end
    i=1:1:100;
     m=sum(i);
     sumb=m*m;
Dif=sumb-suma

答案

25164150