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Happy Number

Accepted : 118   Submit : 303
Time Limit : 1000 MS   Memory Limit : 65536 KB 

Problem Description

Recently, Mr. Xie learn the concept of happy number. A happy number is a number contain all digit 7 or only 1 digit other than 7. For example, 777 is a happy number because 777 contail all digit 7, 7177 and 87777 both happy number because only 1 digit other than 7. Whereas 887,799 9807,12345, all of them are not happy number. Now Mr. xie want to know for a given integer n, how many number among [1,n] are happy numbers, but counting them one by one is slow, can you help him?

Input

First line an integer t indicate there are t testcases(1≤t≤100). Then t lines follow, each line an integer n(1≤n≤106, n don't have leading zero).

Output

Output case number first, then the answer.

Sample Input

5
1
7
17
20
30

Sample Output

Case 1: 1
Case 2: 7
Case 3: 10
Case 4: 10
Case 5: 11


 
题意:所谓欢乐数,就是指一个数所有的位数全部都是7,或是只有一个位上的数不是7。计算从1到n欢乐数的个数,需要注意的是若只有1位,则不管是不是7,
      都是欢乐数。
      开始想找规律,想来想去,还不如暴力简单,毕竟最大只有7位数,那就暴力吧!!暴力万岁!!!!!
 
 
#include 
#include 
#include 
#include 
using namespace std;

int main()
{
    int n,i,t,k,m,sum;
    scanf("%d",&t);
    for(m=1; m<=t; m++)
    {
        sum=9;
        scanf("%d",&n);
        if(n<10)
           {
                printf("Case %d :%d\n",m,n);
                continue;
           }
            for(k=10; k<=n; k++)
            {
                int j=k,p = 0,t1 = 0,w = 0,x;
                while (j)
                {
                    x = j%10;
                    j=j/10;
                    t1++;
                    if(x==7)
                        p++;
                    else w++;
                    if(w>=2)
                        break;
                }
                if(p==t1||p==t1-1)
                    sum++;
            }
            printf("Case %d: %d\n",m,sum);
    }
    return 0;
}


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