Can you solve this equation?


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Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
 

Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
 

Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
 

Sample Input
 
   
2 100 -4
 

Sample Output
 
   
1.6152 No solution!
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
因为f函数是单调递增的,所以可以用二分;
#include
#include
double f(double x)
{
	return (8*x*x*x*x + 7*x*x*x + 2*x*x + 3*x + 6);
}
int main()
{
	int ncase,i,j,k;
	double m,n;
	scanf("%d",&ncase);
	while(ncase--)
	{
		scanf("%lf",&m);
		if(f(0)>m||f(100)1e-5)
		{
		     if((f(mid)>m))
			 {
			 	r=mid;
 				mid=(l+r)/2;	
 			 }	
 			 else if(f(mid)


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