Android适用于IM通知音频的Vibrator

这个帖子代码主要源于:
https://github.com/xiaofei-dev/Vibrator
再此基础上进行稍微修改,代码如下:
使用方式如下:

private VibratorUtil vibratorUtil;
  /**
     * 初始化震动
     */
    private void initVibratorUtil(){
        vibratorUtil = new VibratorUtil((Vibrator)getSystemService(Service.VIBRATOR_SERVICE));
    }
	
	private void startVibrator(){
	        vibratorUtil.setVibratePattern(1000);
		vibratorUtil.vibrate(VibratorUtil.Companion.getINTERRUPT());
	}

	/** 停止震动 */
	private void stop(){
		vibratorUtil.stopVibrate();
	}

源码如下:

//此类用于描述振动属性,即Vibrator类的方法参数值
class VibratorUtil(private val mVibrator: Vibrator) {
    companion object {
        private val TAG = "VibratorUtil"
        //振动模式为断续
        val INTERRUPT = 0
        //振动模式为持续
        val KEEP = 1
        var mPattern = longArrayOf(0, 0, 0)
    }

    //通过设置一个小时时长来模拟持续不停地震动
    private var mDuration = (1000 * 60 * 60).toLong()
    private val mPatternKeep = longArrayOf(1, (1000 * 10).toLong(), 1, (1000 * 10).toLong())
    var isVibrate: Boolean = false
        private set

    private val mAudioAttributes = AudioAttributes.Builder()
            .setContentType(AudioAttributes.CONTENT_TYPE_SONIFICATION)
            .setUsage(AudioAttributes.USAGE_ALARM) //key
            .build()

    fun setDuration(duration: Long) {
        mDuration = duration
    }

    //开始震动
    fun vibrate(mode: Int) {
        Log.d(TAG, "vibrate:0 ")
        isVibrate = true
        when (mode) {
            INTERRUPT -> {
                if (Build.VERSION.SDK_INT >= 21){
                    //适配在高版本系统上无法后台震动的问题
                    mVibrator.vibrate(mPattern, -1, mAudioAttributes)
                }else{
                    mVibrator.vibrate(mPattern, -1)
                }
                Log.d(TAG, "vibrate:0 ")
            }
            KEEP ->
                if (Build.VERSION.SDK_INT >= 21){
                    //适配在高版本系统上无法后台震动的问题
                    mVibrator.vibrate(mPatternKeep, -1, mAudioAttributes)
                }else{
                    mVibrator.vibrate(mPatternKeep, -1)//-1是不循环,如果是0则从0开始
                }
            else -> {
            }
        }
    }

    fun stopVibrate() {
        isVibrate = false
        mVibrator.cancel()
    }

    public fun setVibratePattern(duration: Int) {
//        long[] patter = {1000, 1000, 2000, 50};数组的a[0]表示静止的时间,a[1]代表的是震动的时间,然后数组的a[2]表示静止的时间,a[3]代表的是震动的时间
        mPattern[1] = (duration * 16).toLong()
        mPattern[2] = (duration * 4).toLong()
    }

}

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