sql查询连续3天有交易记录的客户

利用表的自关联查询

表A

CUS_ID	TXN_DT	ID
1	20180101	1
2	20180101	2
3	20180101	3
1	20180102	4
2	20180102	5
2	20180102	6
1	20180103	7
3	20180103	8

with t as (
    select 
        cus_id
        ,txn_dt
    from a
    qualify row_number()over(partition by cus_id,txn_dt order by id ) = 1
              )
select
    cus_id   
from t m
inner join t n
on m.cus_id = n.cus_id
and m.txn_dt <= n.txn_dt +2
group by 1
having count(cus_id) = 3
;
--或者
select
    cus_id   
from a m
inner join a n
on m.cus_id = n.cus_id
and m.txn_dt <= n.txn_dt +2
group by 1
having count(distinct txn_dt) = 3
;

　　

转载于:https://www.cnblogs.com/king-cobra-rko/p/11167458.html