PAT-A-1057 Stack 【桶排序】

Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element). Now you are supposed to implement a stack with an extra operation: PeekMedian -- return the median value of all the elements in the stack. With N elements, the median value is defined to be the (N/2)-th smallest element if N is even, or ((N+1)/2)-th if N is odd.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (≤10​5​​). Then N lines follow, each contains a command in one of the following 3 formats:

Push key
Pop
PeekMedian

where key is a positive integer no more than 10​5​​.

Output Specification:

For each Push command, insert key into the stack and output nothing. For each Pop or PeekMedian command, print in a line the corresponding returned value. If the command is invalid, print Invalid instead.

Sample Input:

17
Pop
PeekMedian
Push 3
PeekMedian
Push 2
PeekMedian
Push 1
PeekMedian
Pop
Pop
Push 5
Push 4
PeekMedian
Pop
Pop
Pop
Pop

Sample Output:

Invalid
Invalid
3
2
2
1
2
4
4
5
3
Invalid

---

暴力算法，Stack保存数据，vector维持数据顺序，只过了两个案例。

#include 
#include 
#include 
#include 
#include 
using namespace std;
int main(){
	int n;
	string flag;
	scanf("%d",&n);
	stack data;
	char s[20];
	vector da;
	int temp;
	for(int l=0;lda[(size/2)-1]?da[(size/2)-1]:da[size/2];
			}
			printf("%d\n",mid);
			
		}

	}
	
	return 0;
}

 

---

stack一定不能丢，解决超时的问题一定是要从vector上入手

不使用vector维护数据列表，是用一个大数据维护.使用桶排序的思想来技术

#include 
#include 
#include 
#include 
#define max 100010
#define v 320
using namespace std;
stack data;
int table[max];
int bucket[v];
void Push(int n){
	data.push(n);
	table[n]++;
	bucket[n/v]++;
}
int Pop(){
	int n=data.top();
	table[n]--;
	bucket[n/v]--;
	data.pop();
	return n;
}


int PeekMedian(){
	int index=(data.size()+1)/2;
	int i=0,j=0;
	while(i+bucket[j]