杭电oj--2005

C++实现:

#include
#include
using namespace std;
int main()
{
     int y,m,d,count=0;
     while(scanf("%d/%d/%d",&y,&m,&d)!=EOF){
         if((y%4==0&&y%100!=0)||y%400==0)  //如果是闰年 
		 {
		 	if(m<=2){
		 		count=(m-1)*31+d;
		 	}
		 	if(m==3){
		 		count=29+31+d;
		 	}
		 	if(m==4){
		 		count=29+31+30+d;
		 	}
		 	if(m==5){
		 		count=29+31*2+30+d;
		 	}
		 	if(m==6){
		 		count=29+31*2+30+31+d;
		 	}
		 	if(m==7){
		 		count=29+31*2+30+31+30+d;
		 	}
		 	if(m==8){
		 		count=29+31*2+30+31+30+31+d;
		 	}
		 	if(m==9){
		 		count=29+31*2+30+31+30+31+31+d;
		 	}
		 	if(m==10){
		 		count=29+31*2+30+31+30+31+31+30+d;
		 	}
		 	if(m==11){
		 		count=29+31*2+30+31+30+31+31+30+31+d;
		 	}
		 	if(m==12){
		 		count=29+31*2+30+31+30+31+31+30+31+30+d;
		 	}
         }
         else{    //如果是平年 
		 	if(m<=2){
		 		count=(m-1)*31+d;
		 	}
		 	if(m==3){
		 		count=28+31+d;
		 	}
		 	if(m==4){
		 		count=28+31+30+d;
		 	}
		 	if(m==5){
		 		count=28+31*2+30+d;
		 	}
		 	if(m==6){
		 		count=28+31*2+30+31+d;
		 	}
		 	if(m==7){
		 		count=28+31*2+30+31+30+d;
		 	}
		 	if(m==8){
		 		count=28+31*2+30+31+30+31+d;
		 	}
		 	if(m==9){
		 		count=28+31*2+30+31+30+31+31+d;
		 	}
		 	if(m==10){
		 		count=28+31*2+30+31+30+31+31+30+d;
		 	}
		 	if(m==11){
		 		count=28+31*2+30+31+30+31+31+30+31+d;
		 	}
		 	if(m==12){
		 		count=28+31*2+30+31+30+31+31+30+31+30+d;
		 	}
         }
         cout<
//可以看出,我的这种方法虽然能够通过,但是效率太低:
//下面是别人的代码:(尊重原作者,来自http://blog.csdn.net/vinacky/article/details/8770356)
#include
#include
using namespace std;
int main()
{
    int a,b,c,d;
    while(scanf("%d/%d/%d",&a,&b,&c)!=EOF)
    {
        d=0;
        if(b<=2)                                                                  //一二月份
            cout<<(b-1)*31+c<
#include
using namespace std;
int main()
{
int a,b,c;
while(scanf("%d/%d/%d",&a,&b,&c)!=EOF)
{
int d=0;
if(((a%4==0&&a%100!=0)||a%400==0)&&b>2) d=1;
for(int i=1;i

//最后附上一个C实现的:(建议把我的当做一个效率的对比)
 
  

 
  
#include
#include
int main()
{
     int y,m,d,count=0;
     while(scanf("%d/%d/%d",&y,&m,&d)!=EOF){
         if((y%4==0&&y%100!=0)||y%400==0)  //如果是闰年 
		 {
		 	if(m<=2){
		 		count=(m-1)*31+d;
		 	}
		 	if(m==3){
		 		count=29+31+d;
		 	}
		 	if(m==4){
		 		count=29+31+30+d;
		 	}
		 	if(m==5){
		 		count=29+31*2+30+d;
		 	}
		 	if(m==6){
		 		count=29+31*2+30+31+d;
		 	}
		 	if(m==7){
		 		count=29+31*2+30+31+30+d;
		 	}
		 	if(m==8){
		 		count=29+31*2+30+31+30+31+d;
		 	}
		 	if(m==9){
		 		count=29+31*2+30+31+30+31+31+d;
		 	}
		 	if(m==10){
		 		count=29+31*2+30+31+30+31+31+30+d;
		 	}
		 	if(m==11){
		 		count=29+31*2+30+31+30+31+31+30+31+d;
		 	}
		 	if(m==12){
		 		count=29+31*2+30+31+30+31+31+30+31+30+d;
		 	}
         }
         else{    //如果是平年 
		 	if(m<=2){
		 		count=(m-1)*31+d;
		 	}
		 	if(m==3){
		 		count=28+31+d;
		 	}
		 	if(m==4){
		 		count=28+31+30+d;
		 	}
		 	if(m==5){
		 		count=28+31*2+30+d;
		 	}
		 	if(m==6){
		 		count=28+31*2+30+31+d;
		 	}
		 	if(m==7){
		 		count=28+31*2+30+31+30+d;
		 	}
		 	if(m==8){
		 		count=28+31*2+30+31+30+31+d;
		 	}
		 	if(m==9){
		 		count=28+31*2+30+31+30+31+31+d;
		 	}
		 	if(m==10){
		 		count=28+31*2+30+31+30+31+31+30+d;
		 	}
		 	if(m==11){
		 		count=28+31*2+30+31+30+31+31+30+31+d;
		 	}
		 	if(m==12){
		 		count=28+31*2+30+31+30+31+31+30+31+30+d;
		 	}
         }
         cout<


 
  

 
  
 
  
 
 

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