统计一个只有1和0的二进制数组,统计1连续出现的最大长度
这道题实在太简单,顺序统计就好,两个变量,一个保存最大值,一个保存当前的连续的1的数量
Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
public class Solution {
public int findMaxConsecutiveOnes(int[] nums) {
int max = 0;
int now = 0;
for(int num:nums){
if (num==1) now++;
else now = 0;
max= Math.max(now,max);
}
return max;
}
}