昨天参加一个笔试的时候,遇到这样一个问题:将阿拉伯数字的钱转换成汉字
package com.dorra.jsoup; import java.math.BigDecimal; public class ConvertNumber { /** 定义数组存放数字对应的大写 */ private final static String[] STR_NUMBER = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" }; /** 定义数组存放位数的大写 */ private final static String[] STR_MODIFY = { "", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟" }; /** * 转化整数部分 * * @param tempString * @return 返回整数部分 */ private static String getInteger(String tempString) { /** 用来保存整数部分数字串 */ String strInteger = null;// /** 记录"."所在位置 */ int intDotPos = tempString.indexOf("."); int intSignPos = tempString.indexOf("-"); if (intDotPos == -1) intDotPos = tempString.length(); /** 取出整数部分 */ strInteger = tempString.substring(intSignPos + 1, intDotPos); strInteger = new StringBuffer(strInteger).reverse().toString(); StringBuffer sbResult = new StringBuffer(); for (int i = 0; i < strInteger.length(); i++) { sbResult.append(STR_MODIFY[i]); sbResult.append(STR_NUMBER[strInteger.charAt(i) - 48]); } sbResult = sbResult.reverse(); replace(sbResult, "零拾", "零"); replace(sbResult, "零佰", "零"); replace(sbResult, "零仟", "零"); replace(sbResult, "零万", "万"); replace(sbResult, "零亿", "亿"); replace(sbResult, "零零", "零"); replace(sbResult, "零零零", "零"); /** 这两句不能颠倒顺序 */ replace(sbResult, "零零零零万", ""); replace(sbResult, "零零零零", ""); /** 这样读起来更习惯. */ replace(sbResult, "壹拾亿", "拾亿"); replace(sbResult, "壹拾万", "拾万"); /** 删除个位上的零 */ if (sbResult.charAt(sbResult.length() - 1) == '零' && sbResult.length() != 1) sbResult.deleteCharAt(sbResult.length() - 1); if (strInteger.length() == 2) { replace(sbResult, "壹拾", "拾"); } /** 将结果反转回来. */ return sbResult.toString(); } /** * 转化小数部分 例:输入22.34返回叁肆 * * @param tempString * @return */ private static String getFraction(String tempString) { String strFraction = null; int intDotPos = tempString.indexOf("."); /** 没有点说明没有小数,直接返回 */ if (intDotPos == -1) return ""; strFraction = tempString.substring(intDotPos + 1); StringBuffer sbResult = new StringBuffer(strFraction.length()); for (int i = 0; i < strFraction.length(); i++) { sbResult.append(STR_NUMBER[strFraction.charAt(i) - 48]); } return sbResult.toString(); } /** * 判断传入的字符串中是否有.如果有则返回点 * * @param tempString * @return */ private static String getDot(String tempString) { return tempString.indexOf(".") != -1 ? "点" : ""; } /** * 判断传入的字符串中是否有-如果有则返回负 * * @param tempString * @return */ private static String getSign(String tempString) { return tempString.indexOf("-") != -1 ? "负" : ""; } /** * 将一个数字转化为金额 * * @param tempNumber 传入一个double的变量 * @return 返一个转换好的字符串 */ public static String numberToChinese(double tempNumber) { java.text.DecimalFormat df = new java.text.DecimalFormat("#.#########"); String pTemp = String.valueOf(df.format(tempNumber)); StringBuffer sbResult = new StringBuffer(getSign(pTemp) + getInteger(pTemp) + getDot(pTemp) + getFraction(pTemp)); return sbResult.toString(); } public static String numberToChinese(BigDecimal tempNumber) { return numberToChinese(tempNumber.doubleValue()); } /** * 替代字符 * * @param pValue * @param pSource * @param pDest */ private static void replace(StringBuffer pValue, String pSource, String pDest) { if (pValue == null || pSource == null || pDest == null) return; /** 记录pSource在pValue中的位置 */ int intPos = 0; do { intPos = pValue.toString().indexOf(pSource); /** 没有找到pSource */ if (intPos == -1) break; pValue.delete(intPos, intPos + pSource.length()); pValue.insert(intPos, pDest); } while (true); } /** * @param args */ public static void main(String[] args) { System.out.println(numberToChinese(1230400567.8934)+"元"); } }