条码(code128)的不同版本实现
好久没写Blog了，这次写写条码（code128)打印的实现。条码在工业应用方面很广泛，所以我们在编写程序时，特别是打印报表时，经常用到。
#region "本段为转载" 转自:http://kaliking.blog.51cto.com/58641/33734
先简述一下CODE128的原理吧,分别以一个unicode字符作为起始符(Ì)和终止符(Î),
然后需要根据你的字符串, 计算出当前字符集的校验码:
ode 128 Barcode Table
| Value |
Code Set A |
Code Set B |
Code Set C |
Bar/Space Pattern B S B S B S |
|---|---|---|---|---|
| 0 |
SP |
SP |
00 |
2 1 2 2 2 2 |
| 1 |
! |
! |
01 |
2 2 2 1 2 2 |
| 2 |
" |
" |
02 |
2 2 2 2 2 1 |
| 3 |
# |
# |
03 |
1 2 1 2 2 3 |
| 4 |
$ |
$ |
04 |
1 2 1 3 2 2 |
| 5 |
% |
% |
05 |
1 3 1 2 2 2 |
| 6 |
& |
& |
06 |
1 2 2 2 1 3 |
| 7 |
' |
' |
07 |
1 2 2 3 1 2 |
| 8 |
( |
( |
08 |
1 3 2 2 1 2 |
| 9 |
) |
) |
09 |
2 2 1 2 1 3 |
| 10 |
* |
* |
10 |
2 2 1 3 1 2 |
| 11 |
+ |
+ |
11 |
2 3 1 2 1 2 |
| 12 |
, |
, |
12 |
1 1 2 2 3 2 |
| 13 |
- |
- |
13 |
1 2 2 1 3 2 |
| 14 |
. |
. |
14 |
1 2 2 2 3 1 |
| 15 |
/ |
/ |
15 |
1 1 3 2 2 2 |
| 16 |
0 |
0 |
16 |
1 2 3 1 2 2 |
| 17 |
1 |
1 |
17 |
1 2 3 2 2 1 |
| 18 |
2 |
2 |
18 |
2 2 3 2 1 1 |
| 19 |
3 |
3 |
19 |
2 2 1 1 3 2 |
| 20 |
4 |
4 |
20 |
2 2 1 2 3 1 |
| 21 |
5 |
5 |
21 |
2 1 3 2 1 2 |
| 22 |
6 |
6 |
22 |
2 2 3 1 1 2 |
| 23 |
7 |
7 |
23 |
3 1 2 1 3 1 |
| 24 |
8 |
8 |
24 |
3 1 1 2 2 2 |
| 25 |
9 |
9 |
25 |
3 2 1 1 2 2 |
| 26 |
: |
: |
26 |
3 2 1 2 2 1 |
| 27 |
; |
; |
27 |
3 1 2 2 1 2 |
| 28 |
< |
< |
28 |
3 2 2 1 1 2 |
| 29 |
= |
= |
29 |
3 2 2 2 1 1 |
| 30 |
> |
> |
30 |
2 1 2 1 2 3 |
| 31 |
? |
? |
31 |
2 1 2 3 2 1 |
| 32 |
@ |
@ |
32 |
2 3 2 1 2 1 |
| 33 |
A |
A |
33 |
1 1 1 3 2 3 |
| 34 |
B |
B |
34 |
1 3 1 1 2 3 |
| 35 |
C |
C |
35 |
1 3 1 3 2 1 |
| 36 |
D |
D |
36 |
1 1 2 3 1 3 |
| 37 |
E |
E |
37 |
1 3 2 1 1 3 |
| 38 |
F |
F |
38 |
1 3 2 3 1 1 |
| 39 |
G |
G |
39 |
2 1 1 3 1 3 |
| 40 |
H |
H |
40 |
2 3 1 1 1 3 |
| 41 |
I |
I |
41 |
2 3 1 3 1 1 |
| 42 |
J |
J |
42 |
1 1 2 1 3 3 |
| 43 |
K |
K |
43 |
1 1 2 3 3 1 |
| 44 |
L |
L |
44 |
1 3 2 1 3 1 |
| 45 |
M |
M |
45 |
1 1 3 1 2 3 |
| 46 |
N |
N |
46 |
1 1 3 3 2 1 |
| 47 |
O |
O |
47 |
1 3 3 1 2 1 |
| 48 |
P |
P |
48 |
3 1 3 1 2 1 |
| 49 |
Q |
Q |
49 |
2 1 1 3 3 1 |
| 50 |
R |
R |
50 |
2 3 1 1 3 1 |
| 51 |
S |
S |
51 |
2 1 3 1 1 3 |
| 52 |
T |
T |
52 |
2 1 3 3 1 1 |
| 53 |
U |
U |
53 |
2 1 3 1 3 1 |
| 54 |
V |
V |
54 |
3 1 1 1 2 3 |
| 55 |
W |
W |
55 |
3 1 1 3 2 1 |
| 56 |
X |
X |
56 |
3 3 1 1 2 1 |
| 57 |
Y |
Y |
57 |
3 1 2 1 1 3 |
| 58 |
Z |
Z |
58 |
3 1 2 3 1 1 |
| 59 |
[ |
[ |
59 |
3 3 2 1 1 1 |
| 60 |
/ |
/ |
60 |
3 1 4 1 1 1 |
| 61 |
] |
] |
61 |
2 2 1 4 1 1 |
| 62 |
^ |
^ |
62 |
4 3 1 1 1 1 |
| 63 |
_ |
_ |
63 |
1 1 1 2 2 4 |
| 64 |
NUL |
` |
64 |
1 1 1 4 2 2 |
| 65 |
SOH |
a |
65 |
1 2 1 1 2 4 |
| 66 |
STX |
b |
66 |
1 2 1 4 2 1 |
| 67 |
ETX |
c |
67 |
1 4 1 1 2 2 |
| 68 |
EOT |
d |
68 |
1 4 1 2 2 1 |
| 69 |
ENQ |
e |
69 |
1 1 2 2 1 4 |
| 70 |
ACK |
f |
70 |
1 1 2 4 1 2 |
| 71 |
BEL |
g |
71 |
1 2 2 1 1 4 |
| 72 |
BS |
h |
72 |
1 2 2 4 1 1 |
| 73 |
HT |
i |
73 |
1 4 2 1 1 2 |
| 74 |
LF |
j |
74 |
1 4 2 2 1 1 |
| 75 |
VT |
k |
75 |
2 4 1 2 1 1 |
| 76 |
FF |
I |
76 |
2 2 1 1 1 4 |
| 77 |
CR |
m |
77 |
4 1 3 1 1 1 |
| 78 |
SO |
n |
78 |
2 4 1 1 1 2 |
| 79 |
SI |
o |
79 |
1 3 4 1 1 1 |
| 80 |
DLE |
p |
80 |
1 1 1 2 4 2 |
| 81 |
DC1 |
q |
81 |
1 2 1 1 4 2 |
| 82 |
DC2 |
r |
82 |
1 2 1 2 4 1 |
| 83 |
DC3 |
s |
83 |
1 1 4 2 1 2 |
| 84 |
DC4 |
t |
84 |
1 2 4 1 1 2 |
| 85 |
NAK |
u |
85 |
1 2 4 2 1 1 |
| 86 |
SYN |
v |
86 |
4 1 1 2 1 2 |
| 87 |
ETB |
w |
87 |
4 2 1 1 1 2 |
| 88 |
CAN |
x |
88 |
4 2 1 2 1 1 |
| 89 |
EM |
y |
89 |
2 1 2 1 4 1 |
| 90 |
SUB |
z |
90 |
2 1 4 1 2 1 |
| 91 |
ESC |
{ |
91 |
4 1 2 1 2 1 |
| 92 |
FS |
| |
92 |
1 1 1 1 4 3 |
| 93 |
GS |
} |
93 |
1 1 1 3 4 1 |
| 94 |
RS |
~ |
94 |
1 3 1 1 4 1 |
| 95 |
US |
DEL |
95 |
1 1 4 1 1 3 |
| 96 |
FNC 3 |
FNC 3 |
96 |
1 1 4 3 1 1 |
| 97 |
FNC 2 |
FNC 2 |
97 |
4 1 1 1 1 3 |
| 98 |
SHIFT |
SHIFT |
98 |
4 1 1 3 1 1 |
| 99 |
CODE C |
CODE C |
99 |
1 1 3 1 4 1 |
| 100 |
CODE B |
FNC 4 |
CODE B |
1 1 4 1 3 1 |
| 101 |
FNC 4 |
CODE A |
CODE A |
3 1 1 1 4 1 |
| 102 |
FNC 1 |
FNC 1 |
FNC 1 |
4 1 1 1 3 1 |
| 103 |
Start A |
Start A |
Start A |
2 1 1 4 1 2 |
| 104 |
Start B |
Start B |
Start B |
2 1 1 2 1 4 |
| 105 |
Start C |
Start C |
Start C |
2 1 1 2 3 2 |
| 106 |
Stop |
Stop |
Stop |
2 3 3 1 1 1 2 |
Example... To calculate the check digit for the barcode data string 'Code 128'
根据上表把没个字符的值 乘上 字符在字符串中的位置从开始算
把没个乘积加起来
因为为这是规定不要问我为什么
所以还要加上
最后除以所得的余数就是 校验码 的值然后在表中找到对应的字符
就可以了
有心人应该注意到了的时候是没有字符的事实上还是有的
只不过是字符
好了原理就阐述到这里还有什么不懂的话大家看看代码好了
至于用在水晶报表上的问题我这里是配合条码字体的我会上传一个我正在用的字体
代码如下
我放大一下上面用到的特殊字符大家看看清楚
起始符
终止符
根据以上代码，这作了几个转换的版本，用于不同的环境，
版本：
中版本：
版本（注：此版本只能在支持的中应用）：