Mac环境下shell脚本中的map

Linux 上服务执行脚本时运行正常，切换到Mac上之后如下脚本一直报错

Linux 上服务执行脚本时运行正常

[duan@dev ~]$ cat cmd.sh
#!/bin/bash
declare -A map=(["c"]="C" ["java"]="JAVA" ["go"]="GO")
echo ${map[go]}
[duan@dev ~]$ sh cmd.sh
GO
[duan@dev ~]$ echo $BASH_VERSION
4.2.46(1)-release

本地Mac 错误如下

bash-3.2$ sh cmd.sh
d.sh: line 2: declare: -A: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
GO

Mac OS X 的默认Bash 是3.x版本，不支持map这种数据结构

bash-3.2$ help declare
declare: declare [-afFirtx] [-p] [name[=value] ...]
    Declare variables and/or give them attributes.  If no NAMEs are
    given, then display the values of variables instead.  The -p option
    will display the attributes and values of each NAME.

    The flags are:

      -a    to make NAMEs arrays (if supported)
      -f    to select from among function names only
      -F    to display function names (and line number and source file name if
        debugging) without definitions
      -i    to make NAMEs have the `integer' attribute
      -r    to make NAMEs readonly
      -t    to make NAMEs have the `trace' attribute
      -x    to make NAMEs export

    Variables with the integer attribute have arithmetic evaluation (see
    `let') done when the variable is assigned to.

    When displaying values of variables, -f displays a function's name
    and definition.  The -F option restricts the display to function
    name only.

    Using `+' instead of `-' turns off the given attribute instead.  When
    used in a function, makes NAMEs local, as with the `local' command.

所以有两种解决方案：

1. 升级bash到 4.x 以上版本

2. 用其他方式:比如 if elif 去到达相同的结果

echo $name
name="c"
if [ $name == "c" ]
then
   language="C"
elif [ $name == "java" ]
then
   language="JAVA"
elif [ $name == "go" ]
then
   language="GO"
else
   language="unknow"
fi
echo "language=$language"