题目来源:点击进入【CodeForces 1366B— Shuffle】
Description
You are given an array consisting of n integers a1, a2, …, an. Initially ax=1, all other elements are equal to 0.
You have to perform m operations. During the i-th operation, you choose two indices c and d such that li≤c,d≤ri, and swap ac and ad.
Calculate the number of indices k such that it is possible to choose the operations so that ak=1 in the end.
Input
The first line contains a single integer t (1≤t≤100) — the number of test cases. Then the description of t testcases follow.
The first line of each test case contains three integers n, x and m (1≤n≤109; 1≤m≤100; 1≤x≤n).
Each of next m lines contains the descriptions of the operations; the i-th line contains two integers li and ri (1≤li≤ri≤n).
Output
For each test case print one integer — the number of indices k such that it is possible to choose the operations so that ak=1 in the end.
Sample Input
3
6 4 3
1 6
2 3
5 5
4 1 2
2 4
1 2
3 3 2
2 3
1 2
Sample Output
6
2
3
Note
In the first test case, it is possible to achieve ak=1 for every k. To do so, you may use the following operations:
In the second test case, only k=1 and k=2 are possible answers. To achieve a1=1, you have to swap a1 and a1 during the second operation. To achieve a2=1, you have to swap a1 and a2 during the second operation.
AC代码(C++):
#include
#include
#define SIS std::ios::sync_with_stdio(false),cin.tie(0),cout.tie(0)
#define endl '\n'
using namespace std;
typedef long long ll;
const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const int MAXN = 1e5+5;
int main(){
SIS;
int t,n,x,m,a,b,l,r;
cin >> t;
while(t--){
cin >> n >> x >> m;
l=r=x;
while(m--){
cin >> a >> b;
if(b<l || a>r) continue;
l=min(l,a);
r=max(r,b);
}
cout << r-l+1 << endl;
}
return 0;
}