uva 401(字符串)

题目：

A regular palindrome is a string of numbers or letters that is the same forward as backward. For example, the string"ABCDEDCBA" is a palindrome because it is the same when the string is read from left to right as when the string is read from right to left.

 

A mirrored string is a string for which when each of the elements of the string is changed to its reverse (if it has a reverse) and the string is read backwards the result is the same as the original string. For example, the string"3AIAE" is a mirrored string because "A" and "I" are their own reverses, and"3" and "E" are each others' reverses.

A mirrored palindrome is a string that meets the criteria of a regular palindrome and the criteria of a mirrored string. The string"ATOYOTA" is a mirrored palindrome because if the string is read backwards, the string is the same as the original and because if each of the characters is replaced by its reverse and the result is read backwards, the result is the same as the original string.

Of course,"A","T","O", and"Y" are all their own reverses.

A list of all valid characters and their reverses is as follows.

Character	Reverse	Character	Reverse	Character	Reverse
A	A	M	M	Y	Y
B		N		Z	5
C		O	O	1	1
D		P		2	S
E	3	Q		3	E
F		R		4
G		S	2	5	Z
H	H	T	T	6
I	I	U	U	7
J	L	V	V	8	8
K		W	W	9
L	J	X	X

Note that O (zero) and 0 (the letter) are considered the same character and thereforeONLY the letter "0" is a valid character.

input 

Input consists of strings (one per line) each of which will consist of one to twenty valid characters. There will be no invalid characters in any of the strings. Your program should read to the end of file.

output

For each input string, you should print the string starting in column 1 immediately followed by exactly one of the following strings.

STRING	CRITERIA
" -- is not a palindrome."	if the string is not a palindrome and is not a mirrored string
" -- is a regular palindrome."	if the string is a palindrome and is not a mirrored string
" -- is a mirrored string."	if the string is not a palindrome and is a mirrored string
" -- is a mirrored palindrome."	if the string is a palindrome and is a mirrored string

Note that the output line is to include the-'s and spacing exactly as shown in the table above and demonstrated in the Sample Output below.

In addition, after each output line, you must print an empty line.

sample input

NOTAPALINDROME
ISAPALINILAPASI
2A3MEAS
ATOYOTA

sample output

NOTAPALINDROME -- is not a palindrome.
 
ISAPALINILAPASI -- is a regular palindrome.
 
2A3MEAS -- is a mirrored string.
 
ATOYOTA -- is a mirrored palindrome.

题解：回文是对称相同，镜像是上边的表格，4种不同的情况输出不同的后缀语句，输出每行后有空行。注意0和O等价。

#include 
#include 
#include 
#include 
int main() {
	char rev[35] = {'A',' ',' ',' ','3',' ',' ','H','I','L',' ','J',
					'M',' ','O',' ',' ',' ','2','T','U','V','W','X',
					'Y','5','1','S','E',' ','Z',' ',' ','8',' '};
	char que[25];
	int flag1, flag2;
	while (~scanf("%s", que)){
		getchar();
		flag1 = 0;
		flag2 = 0;
		int i, j;
		int length = strlen(que);
		for (i = 0, j = length - 1; i < length / 2; i++, j--){
			if (que[i] == que[j])
				flag1++;
			if (que[i] >= 'A' && que[i] <= 'Z'){
				int a = que[i] - 'A';
				if (rev[a] == que[j])
					flag2++;
			}
			if (que[i] >= '1' && que[i] <= '9'){
				int b = que[i] - '1' + 26;
				if (rev[b] == que[j])
					flag2++;
			}
            if ((que[i] == '0' && que[j] == 'O') || (que[i] == 'O' && que[j] == '0')){
                flag1++;
                flag2++;
            }
            if(que[i] == '0' && que[j] == '0')
                flag2++;
		}
		if (length % 2 != 0){
			int c = que[length / 2] - 'A';
			if (rev[c] == que[length / 2 ] || que[length / 2 ] == '1' || que[length / 2 ] == '8' || que[length / 2 ] == '0')
				flag2++;
			flag1++;
			if (length / 2 + 1 == flag1 && flag1 == flag2)
				printf("%s -- is a mirrored palindrome.\n\n", que);
			else if (flag2 == length / 2 + 1 )
				printf("%s -- is a mirrored string.\n\n", que);
			else if (flag1 == length / 2 + 1)
				printf("%s -- is a regular palindrome.\n\n", que);
			else
				printf("%s -- is not a palindrome.\n\n", que);
		}
		if (length % 2 == 0){
			if (length / 2 == flag1 && flag1 == flag2)
				printf("%s -- is a mirrored palindrome.\n\n", que);
			else if (flag2 == length / 2)
				printf("%s -- is a mirrored string.\n\n", que);
			else if (flag1 == length / 2)
				printf("%s -- is a regular palindrome.\n\n", que);
			else
				printf("%s -- is not a palindrome.\n\n", que);
		}
	}
	return 0;
}