ACM HDU 1012

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 12753    Accepted Submission(s): 5485


Problem Description
A simple mathematical formula for e is

ACM HDU 1012

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
 

Source
 

Recommend
JGShining
 
水题,太简单
#include<stdio.h>
#include
<iostream>
using namespace std;
int main()
{
int i;
double e=2.5;
double a=0.5;
printf(
"n e\n- -----------\n0 1\n1 2\n2 2.5\n");
for(i=3;i<=9;i++)
{
a
=a/i;
e
+=a;
printf(
"%d %.9lf\n",i,e);
}
//system("pause");
return 0;
}

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