快速排序的实现(c语言)

以前写的代码

 

//

//  main.c

//  cTest

//

//  Created by Zizhu on 13-10-8.

//  Copyright (c) 2013年 Zizhu. All rights reserved.

//



#include <stdio.h>



#define N (10)



void quickSor(int *nums, int indexStart, int indexEnd);

int  partition(int *nums, int indexStart, int indexEnd);

void exchange(int *nums, int p1, int p2);

void printNums(int *nums, int count);



int main()

{

	printf(">>>strat\n");

	int nums[N] = {0, 4, 2, 5, 1, 3, -1, 19, 99, -100};

	printNums(nums, N);

	int mid = partition(nums, 0, N-1);

	printNums(nums, N);

	printf("mid = %d\n", mid);

	quickSor(nums, 0, N-1);

	printNums(nums, N);

	return 0;

}



void quickSor(int *nums, int indexStart, int indexEnd)

{

	if (indexEnd > indexStart)

	{

		int indexMid = partition(nums, indexStart, indexEnd);

		quickSor(nums, indexStart, indexMid-1);

		quickSor(nums, indexMid+1, indexEnd);

	}

	

}



int partition(int *nums, int indexStart, int indexEnd)

{

    

	int p2 = indexStart-1;

	int p1;

    

	int target = nums[indexEnd];

    

	for (p1 = indexStart; p1 < indexEnd; p1++)

	{

		if (nums[p1] <= target)

		{

			p2++;

			exchange(nums, p1, p2);

			

		}

	}

	exchange(nums, p2+1, indexEnd);

	return p2+1;

}



void exchange(int *nums, int p1, int p2)

{

	int tmp = nums[p1];

	nums[p1] = nums[p2];

	nums[p2] = tmp;

}



void printNums(int *nums, int count)

{

	printf("numbers : ");

	int i;

	for (i = 0; i < count; ++i)

	{

		printf("%4d\t", nums[i]);

	}

	printf("\n");

}