设计一个算法，计算 Huffman 树的带权路径长度。

设计一个算法，计算 Huffman 树的带权路径长度。

#include
#include
#include
#include
#include
using namespace std;
typedef struct
{
     
	int data;
	int parent;
	int leftChild, rightChild;
}node;
node* treee;

int Huffman(int* a, int n)
{
     
	int ans = 0;
	node tree[200];//数组+指针，十字链表法？！

	int m = 2 * n - 1;                              //节点总数
	int i;
	for (i = 0; i < n; i++)
		tree[i].data = a[i];

	for (i = 0; i < m; i++)                      //初始化每个节点
	{
     
		tree[i].parent = NULL;
		tree[i].leftChild = NULL;
		tree[i].rightChild = NULL;
	}
	for (i = n; i < m; i++)                      //非叶子节点
	{
     
		int min1 = 1000000, min2 = 1000000;
		int pos1 = 0, pos2 = 0;                             //第一小和第二小
		int j;
		for (j = 0; j < i; j++)                  //叶子节点
		{
     
			if (tree[j].parent == NULL)//还没进构成树的结点
			{
     
				if (tree[j].data < min1)
				{
     
					//swap();
					pos2 = pos1;
					pos1 = j;
					min2 = min1;
					min1 = tree[j].data;
				}
				else if (tree[j].data < min2)
				{
     
					min2 = tree[j].data;
					pos2 = j;
				}
			}
		}
		tree[i].leftChild = min(pos1, pos2);
		tree[i].rightChild = max(pos1, pos2);
		tree[i].data = tree[pos1].data + tree[pos2].data;
		tree[pos1].parent = i;
		tree[pos2].parent = i;
		ans += tree[i].data;
	}
	treee = tree;//为了把构造好的哈夫曼树用全局变量传递出来
	return ans;//哈夫曼树最小权值
}


int main()
{
     
	int num[120];
	int n;
	printf("比如：用5个带权值{3,2,4,5,1}构造的哈夫曼树的带权路径长度\n");
	//n个数字，排列出哈夫曼树
	printf("请输入要输入的元素的个数\n");
	scanf("%d",&n);
	printf("请输入各个元素的值（非负数）\n");
	for (int i = 0; i < n; i++)
		scanf("%d",&num[i]);
	printf("所得结果：%d",Huffman(num, n) );
}