pre
public synchronized List queryAccountViaTag(String tag, Boolean isLock) {
List acc = new ArrayList<>();
if (tag.contains("&") && !tag.contains("_sc") && !tag.contains("_dc") && !tag.contains("_conference")) {
String[] separateTag = tag.split("&");
for (String getTag : separateTag) {
acc.addAll(queryAccountFromDB(getTag, 1, "RM", isLock));
}
} else if (tag.contains("&") && (tag.contains("_sc") || tag.contains("_dc") || tag.contains("_conference"))) {
String[] separateTag = tag.split("&");
List tagList = Arrays.asList(separateTag);
Set uniqueSet = new HashSet<>(tagList);
Map map = new HashMap();
for (String temp : uniqueSet) {
Integer count = Collections.frequency(tagList, temp);
map.put(temp, count);
}
for (Map.Entry entry : map.entrySet()) {
logger.info("Key = " + entry.getKey() + ", Value = " + entry.getValue());
String getTag;
if(entry.getKey().endsWith("_sc")) {
getTag = entry.getKey().replace("_sc", "");
acc.addAll(queryAccountFromDB(getTag, entry.getValue(), "SC", isLock));
} else if (entry.getKey().endsWith("_dc")) {
getTag = entry.getKey().replace("_dc", "");
acc.addAll(queryAccountFromDB(getTag, entry.getValue(), "DC", isLock));
} else if (entry.getKey().endsWith("_conference")) {
getTag = entry.getKey().replace("_conference","");
acc.addAll(queryAccountFromDB(getTag, entry.getValue(),"CF", isLock));
}
else {
getTag = entry.getKey();
acc.addAll(queryAccountFromDB(getTag, 1, "RM",isLock));
}
}
} else {
if(tag.endsWith("_sc")) {
tag = tag.replace("_sc", "");
}
if(tag.endsWith("_dc")) {
tag = tag.replace("_dc", "");
}
if(tag.endsWith("_conference")) {
tag = tag.replace("_conference","");
acc = queryAccountFromDB(tag, 1, "CF", isLock);
} else {
acc = queryAccountFromDB(tag, 1, "RM", isLock);
}
}
return acc;
}
之前的版本,一个方法里非常非常非常的冗长,如果有什么新的需求的话,又要再继续if...else...,这是很可怕的事情
把需求重新捋一遍,重新把它们拆开,虽然看着改版后的代码好像更长了,但是如果有新需求的话,只要在map里加一条记录即可
after
# 不同的类型的账号需求
public static Map tagTailMapping =new HashMap(){{
put("_dc", "DC");
put("_sc", "SC");
put("_conference", "CF");
}};
# 主体方法
public synchronized List queryAccountViaTag(String tag, Boolean isLock) {
List acc = new ArrayList<>();
Map map = new HashMap<>();
# 根据提供的tag串,是否有包含&。再根据优先返回原则,最容易判断的条件优先返回,可以提高代码运行效率
if (!tag.contains("&")) {
acc = queryTailTagAccounts(tag, 1, isLock);
return acc;
}
if (tag.contains("&")) {
String[] separateTag = tag.split("&");
List tagList = Arrays.asList(separateTag);
map = convertListToUniqueMap(tagList);
}
for (Map.Entry entry : map.entrySet()) {
logger.info("Key = " + entry.getKey() + ", Value = " + entry.getValue());
acc.addAll(queryTailTagAccounts(entry.getKey(), entry.getValue(), isLock));
}
return acc;
}
# 需求是根据不同账号提供的tag最后一个_xx来决定需要运行什么方法
private List queryTailTagAccounts(String tag, int num, Boolean isLock) {
List acc = new ArrayList<>();
String getTag;
String tailTag = tag.contains("_") ? tag.substring(tag.lastIndexOf("_")) : ""; #获取最后一个 _xx,再把对应的type传进去
if (tagTailMapping.containsKey(tailTag)) {
getTag = tag.replace(tailTag, "");
acc.addAll(queryAccountFromDB(getTag, num, tagTailMapping.get(tailTag), isLock));
}
else {
for (int i = 0; i < num; i++) {
acc.addAll(queryAccountFromDB(tag, 1, "RM", isLock));
}
}
return acc;
}
# 把tag串解析出来的list进行处理,减少运行时间
private Map convertListToUniqueMap(List tagList) {
Set uniqueSet = new HashSet<>(tagList);
Map map = new HashMap();
for (String temp : uniqueSet) {
Integer count = Collections.frequency(tagList, temp);
String tailTag = temp.contains("_") ? temp.substring(temp.lastIndexOf("_")) : "";
if (count == 1 && tagTailMapping.containsKey(tailTag)){
temp = temp.replace(tailTag, "");
putMapping(map, temp, count);
} else {
putMapping(map, temp, count);
}
}
return map;
}
private void putMapping(Map map, String temp, Integer count) {
if (map.containsKey(temp)) {
map.put(temp, map.get(temp) + count);
} else {
map.put(temp, count);
}
}