Hdu3233Matrix Power Series矩阵

前面就做过了。。。二分搞下

#include <cstdio>

#include <algorithm>

#include <iostream>

#include <string.h>

typedef long long LL;

using namespace std;

int n, M;

struct Matrix

{

    int m[40][40];

};



Matrix Mul(Matrix a, Matrix b)

{

    Matrix ans;

    for (int i = 0; i < n;i++)

    for (int j = 0; j < n; j++){

        ans.m[i][j] = 0;

        for (int k = 0; k < n; k++){

            ans.m[i][j] += a.m[i][k] * b.m[k][j];

            ans.m[i][j] %= M;

        }

    }

    return ans;

}



Matrix quick(Matrix a, int b)

{

    Matrix ans;

    for (int i = 0; i < n;i++)

    for (int j = 0; j < n; j++)

        ans.m[i][j] = (i == j);

    while (b){

        if (b & 1) ans = Mul(ans, a);

        a = Mul(a, a);

        b >>= 1;

    }

    return ans;

}



Matrix add(Matrix a, Matrix b)

{

    for (int i = 0; i < n;i++)

    for (int j = 0; j < n; j++)

        a.m[i][j] += b.m[i][j], a.m[i][j] %= M;

    return a;

}



Matrix gao(Matrix a, int len)

{

    if (len == 1) return a;

    Matrix ans;

    for (int i = 0; i < n;i++)

    for (int j = 0; j < n; j++) ans.m[i][j] = 0;

    Matrix t = gao(a, len >> 1);

    ans = add(ans, t);

    ans = add(ans, Mul(t, quick(a, (len >> 1))));

    if (len & 1) return add(ans, quick(a, len));

    else return ans;

}



int main()

{

    int k;

    while (cin >> n >> k >> M){

        Matrix ans;

        for (int i = 0; i < n;i++)

        for (int j = 0; j < n; j++)

            scanf("%d", &ans.m[i][j]);

        Matrix sum = gao(ans, k);

        for (int i = 0; i < n; i++){

            for (int j = 0; j < n; j++)

                cout << sum.m[i][j] << " ";

            cout << endl;

        }

    }

    return 0;

}

 

你可能感兴趣的:(Matrix)