页面添加内容后弹出框与跳转页面

     [HttpPost]

        public ActionResult Form(NewsModel model)

        {

            if (ModelState.IsValid)

            {

                if (model.Id == 0)

                {

                    cmd.Add(model);

                }

                else

                {

                    cmd.Update(model.Id, model);

                }

                ViewBag.Msg = "添加成功！";

                ViewBag.ReturnUrl = "/News/List";

            }

            return View();

        }

 <script type="text/javascript">

        $(document).ready(function () {

            if ('@ViewBag.Msg' != null && '@ViewBag.Msg' != "") {

                if (confirm('@ViewBag.Msg' + ',是否继续添加')) {

                        window.location.href = 'Form';

                    }

                    else {

                        window.location.href = '@ViewBag.ReturnUrl';

            }

        }

        });



    </script>

需要引JS包