http://poj.org/problem?id=3080
还是和3450一样的。
code:
#include<cstdio>
//
最长公共子串
#include<cstring>
#define Max(a, b) a>b?a:b
const
int maxn =
650 ;
int wa[maxn], wb[maxn], wv[maxn], ws[maxn], rank[maxn], height[maxn], sa[maxn], s[maxn], loc[maxn] ;
char str[
61], ans[
101] ;
bool vis[
101] ;
int m ;
int cmp(
int *r,
int a,
int b,
int l){
return r[a]==r[b] && r[a+l]==r[b+l] ;
}
void da(
int *r,
int n,
int m){
int i, j, p, *x = wa, *y = wb, *t ;
for(i=
0; i<m; i++) ws[i] =
0 ;
for(i=
0; i<n; i++) ws[x[i]=r[i]] ++ ;
for(i=
1; i<m; i++) ws[i] += ws[i-
1] ;
for(i=n-
1; i>=
0; i--) sa[--ws[x[i]]] = i ;
for(j=
1,p=
1; p<n; j*=
2, m=p){
for(p=
0,i=n-j; i<n; i++) y[p++] = i ;
for(i=
0; i<n; i++)
if(sa[i]>=j) y[p++] = sa[i] - j ;
for(i=
0; i<n; i++) wv[i] = x[y[i]] ;
for(i=
0; i<m; i++) ws[i] =
0 ;
for(i=
0; i<n; i++) ws[wv[i]] ++ ;
for(i=
1; i<m; i++) ws[i] += ws[i-
1] ;
for(i=n-
1; i>=
0; i--) sa[--ws[wv[i]]] = y[i] ;
for(t=x, x=y, y=t, p=
1, x[sa[
0]]=
0, i=
1; i<n; i++)
x[sa[i]] = cmp(y, sa[i-
1], sa[i], j) ? p -
1 : p ++ ;
}
return ;
}
void calheight(
int *r,
int n){
int i, j, k =
0 ;
for(i=
1; i<=n; i++) rank[sa[i]] = i ;
//
获取rank值 O(n)
for(i=
0; i<n; height[rank[i++]]=k)
for(k?k--:
0, j=sa[rank[i]-
1]; r[i+k]==r[j+k]; k++) ;
return ;
}
int check(
int mid,
int len){
int count =
0 ;
memset(vis,
false,
sizeof(vis)) ;
for(
int i=
2; i<=len; i++){
if(height[i]<mid){
memset(vis,
false,
sizeof(vis)) ;
count =
0 ;
continue ;
}
if(!vis[loc[sa[i-
1]]]) vis[loc[sa[i-
1]]] =
true, count ++ ;
if(!vis[loc[sa[i]]]) vis[loc[sa[i]]] =
true, count ++ ;
if(count==m){
for(
int j=
0; j<mid; j++)
ans[j] = s[sa[i]+j] +
'
A
' -
1 ;
ans[mid] =
'
\0
' ;
return
1 ;
}
}
return
0 ;
}
int main(){
int t, n, i, j, max, temp, flag ;
scanf(
"
%d
", &t) ;
while(t--){
n =
0 , temp =
30, flag =
0 ;
scanf(
"
%d
", &m) ;
for(i=
1; i<=m; i++){
scanf(
"
%s
", str) ;
for(j=
0; j<
60; j++){
loc[n] = i ;
s[n++] = str[j] -
'
A
' +
1 ;
}
loc[n] = temp ;
s[n++] = temp ++ ;
}
s[n] =
0 ;
da(s, n+
1, temp) ;
calheight(s, n) ;
int left=
0, right=
60, mid ;
while(right>=left){
mid = (right + left) /
2 ;
if(check(mid, n)){
left = mid +
1 ;
flag = mid ;
}
else
right = mid -
1 ;
}
if(flag>=3) printf(
"
%s\n
", ans) ;
//
若flag为ans长度的话是>=3
else printf(
"
no significant commonalities\n
") ;
}
return
0 ;}