Number of Islands

今天出来的新题,已经有大神出结果了,刚开始看还没看懂,就是dfs + 二维渲染 图 

http://www.cnblogs.com/easonliu/p/4402077.html

public class Solution {

    public int numIslands(char[][] grid) {

        //http://www.cnblogs.com/easonliu/p/4402077.html

        if(grid==null || grid.length==0 || grid[0].length==0) return 0;

        int cnt = 0;

        for(int i=0; i<grid.length; i++){

            for(int j=0; j< grid[0].length; j++){

                if(grid[i][j]=='1'){ // 找到一个尚未被渲染的island

                    cnt++;

                    dfs(grid, i, j);// 感染列岛

                }

            }

        }

        return cnt;

    }

    

    public void dfs(char[][] grid, int x, int y){

        if(y >= grid[0].length|| x >= grid.length|| x<0 || y<0) return;

        if(grid[x][y] == '1') {

            grid[x][y] ='X';

        }else return;

        dfs(grid,x+1,y);

        dfs(grid,x-1,y);

        dfs(grid,x,y+1);

        dfs(grid,x,y-1);

    }

}

 

你可能感兴趣的:(number)