HEU 1034 Calories from Fat

/**/ /**************************************
Problem: HEU 1034 Calories from Fat
Time: 0.0180 s
Memory: 588 k 
Accepted Time: 2009-05-06 17:51:46
Tips: 
**************************************/
#include  < stdio.h >
#include  < string .h >
struct  stru
{
    int num;
    double per;
} percent[ 5 ];
int  main()
{
    char temp[5];
    int exitflag=0,i;
    double a[5]={0,0,0,0,0},sum;
    while(1)
    {
        scanf("%s",temp);
        if(temp[0]=='-')
        {
            if(exitflag)break;
            else 
            {
                exitflag=1;
                sum=0;
                for(i=0;i<5;i++)
                {
                    sum+=a[i];
                }
                printf("%.0lf%%\n",a[0]/sum*100.0);
                for(i=0;i<5;i++)a[i]=0;
            }
        }
        else
        {
            exitflag=0;
            int table[]={9,4,4,4,7},count=0;
            double ptemp=0,gtemp=0;
            for(i=0;i<5;i++)
            {
                if(i!=0)scanf("%s",temp);
                int len=strlen(temp);
                double dtemp;
                switch(temp[len-1])
                {
                    case 'g':
                        sscanf(temp,"%lfg",&dtemp);
                        a[i]+=dtemp*table[i];
                        gtemp+=dtemp*table[i];
                        break;
                    case 'C':
                        sscanf(temp,"%lfC",&dtemp);
                        a[i]+=dtemp;
                        gtemp+=dtemp;
                        break;
                    case '%':
                        sscanf(temp,"%lf%%",&dtemp);
                        ptemp+=dtemp;
                        percent[count].num=i;
                        percent[count].per=dtemp;
                        count++;
                        break;
                }
            }
            if(count!=0)
            {
                sum=gtemp/(100.0-ptemp)*100.0;
                for(i=0;i<count;i++)
                {
                    a[percent[i].num]+=sum/100.0*percent[i].per;
                }
            }
        }
    }
    return 0;
}