POJ The Game
原题目：传送锚点
1.题目
The Game
Description
A game of Renju is played on a 19*19 board by two players. One player uses black stones and the other uses white stones. The game begins in an empty board and two players alternate in placing black stones and white stones. Black always goes first. There are 19 horizontal lines and 19 vertical lines in the board and the stones are placed on the intersections of the lines.
Horizontal lines are marked 1, 2, ..., 19 from up to down and vertical lines are marked 1, 2, ..., 19 from left to right.
The objective of this game is to put five stones of the same color consecutively along a horizontal, vertical, or diagonal line. So, black wins in the above figure. But, a player does not win the game if more than five stones of the same color were put consecutively.
Given a configuration of the game, write a program to determine whether white has won or black has won or nobody has won yet. There will be no input data where the black and the white both win at the same time. Also there will be no input data where the white or the black wins in more than one place.
Input
The first line of the input contains a single integer t (1 <= t <= 11), the number of test cases, followed by the input data for each test case. Each test case consists of 19 lines, each having 19 numbers. A black stone is denoted by 1, a white stone is denoted by 2, and 0 denotes no stone.
Output
There should be one or two line(s) per test case. In the first line of the test case output, you should print 1 if black wins, 2 if white wins, and 0 if nobody wins yet. If black or white won, print in the second line the horizontal line number and the vertical line number of the left-most stone among the five consecutive stones. (Select the upper-most stone if the five consecutive stones are located vertically.)
Sample Input
1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 1 2 0 0 2 2 2 1 0 0 0 0 0 0 0 0 0 0
0 0 1 2 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0
0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 2 2 0 0 0 0 0 0 0 0 0 0 0 0
0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 2 1 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0Sample Output
1
3 22.中文翻译
游戏
描述
两个玩家在一块19*19的木板上玩一场连珠游戏。一个玩家使用黑色石头，另一个使用白色石头。游戏在一块空木板上开始，两名玩家交替放置黑色石头和白色石头。黑色总是排在第一位。木板上有19条水平线和19条垂直线，石头放在这些线的交点上。
给定游戏的配置，编写一个程序来确定是白赢了，还是黑赢了，或者还没有人赢。不会有黑和白同时获胜的输入数据。此外，也不会有白或黑在多个地方获胜的输入数据。
输入
输入的第一行包含一个整数t（1<=t<=11），即测试用例的数量，后面是每个测试用例的输入数据。每个测试用例由19行组成，每行有19个数字。黑色石头用1表示，白色石头用2表示，0表示没有石头。
输出
每个测试用例应该有一到两行。在测试用例输出的第一行中，如果黑获胜，则应该打印1，如果白获胜，则打印2，如果还没有人获胜，则应打印0。如果黑或白获胜，则在第二行打印连续五块石头中最左边石头的水平线编号和垂直线编号。（如果五块连续的石头垂直放置，则选择最上面的石头。）
样例输入
1
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 1 2 0 0 2 2 2 1 0 0 0 0 0 0 0 0 0 0
0 0 1 2 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0
0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 2 2 0 0 0 0 0 0 0 0 0 0 0 0
0 0 1 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 2 1 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0样例输出
1
3 23.代码实现（思路看注释足矣）
#encoding=utf-8
def check_winner(board):
# 检查横向
for i in range(19):
for j in range(15):
if board[i][j] == board[i][j + 1] == board[i][j + 2] == board[i][j + 3] == board[i][j + 4] and board[i][
j] != 0:
return (board[i][j], i + 1, j + 1)
# 检查竖向
for i in range(15):
for j in range(19):
if board[i][j] == board[i + 1][j] == board[i + 2][j] == board[i + 3][j] == board[i + 4][j] and board[i][
j] != 0:
return (board[i][j], i + 1, j + 1)
# 检查左上到右下的斜线
for i in range(15):
for j in range(15):
if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2] == board[i + 3][j + 3] == board[i + 4][
j + 4] and board[i][j] != 0:
return (board[i][j], i + 1, j + 1)
# 检查左下到右上的斜线
for i in range(4, 19):
for j in range(15):
if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2] == board[i - 3][j + 3] == board[i - 4][
j + 4] and board[i][j] != 0:
return (board[i][j], i + 1, j + 1)
# 如果没有获胜者
return (0, 0, 0)
t = int(input())
for _ in range(t):
board = [list(map(int, input().split())) for _ in range(19)]
winner, row, col = check_winner(board)
print(winner)
if winner != 0:
print(row, col)