#将元组(1,2,3) 和集合{"four",5,6}合成一个列表
def syn(x,y):
my_list = []
for zin x:
my_list.append(z)
for jin y :
my_list.append(j)
return my_list
print(syn((1,2,3),{"four",5,6}))
# 将列表[3,7,0,5,1,8]中大于5元素置为0，小于5的元素置为1
def divide(list):
my_list=[]
for xin list:
if x >5:
my_list.append("0")
else:
my_list.append("1")
return my_list
zj = [3,7,0,5,1,8]
print(divide(zj))
# 将列表["mo","deng","ge"]和[1,2,3] 转换成[("mo",1),("deng",2),("ge",3)]
list1 = ["mo","deng","ge"]
list2 = [1,2,3]
list3 = [{k: v}for k, vin zip(list1, list2)]
print(list3)
# 若a = dict(),令 b = a,执行b.update({"x":1}),a亦改变，为何，如何避免
dict = {'mo':1,'deng':2,'ge':3}
a = dict
print(a)
b = a
b.update({"x":1})
print(a)
# 以上证明 b = a 只是变量的赋值，为浅拷贝，拷贝的内存地址
# 避免
import copy
b=copy.deepcopy(a)
b.update({"z":1})
print(a)
print(b)
# 将二维结构[['a',1],['b',2]]和(('x',3),('y',4))转换成字典
list1 = [['a',1],['b',2],['c',3]]
tuple = (('x',3),('y',4))
def chang_type(list):
list1=[]
list2=[]
list3=[]
for iin range(len(list)):
for jin range(len(list[i])):
z = list[i][j]
list1.append(z)
for xin range(len(list1)):
if x %2 ==0:
f = list1[x]
list2.append(f)
else:
m = list1[x]
list3.append(m)
list4 = [{k: v}for k, vin zip(list2, list3)]
return list4
print(chang_type(tuple))
print(chang_type(list1))