C++对于ATM机的队列模拟

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通过设置简单的队列模型,应用到ATM机上去模拟一些数据的获取,详细的代码如下:

//description.h

#ifndef _DESCRIPTION_H_

#define _DESCRIPTION_H_

#include

const int MAX_QUEUE = 100;

using namespace std;

class Customer

{

private:

long processtime;

long begin_time;

public:

Customer(){ processtime = 0; begin_time = 0; }

~Customer(){}

void set(long t);

long get_bt(){ return begin_time; }

long get_pt(){ return processtime; }

};

typedef Customer Item;

class Queue

{

private:

struct Node

{

Item item;

Node *next;

};

Node *front, *rear;

int num;

const int Max_num;

Queue(const Queue &q):Max_num(0){}

Queue & operator=(const Queue &q){ return *this; }

public:

Queue(int Size=MAX_QUEUE);

~Queue();

bool isempty() const { return num==0; }

bool isfull()const { return num == Max_num; }

int get_num() const { return num; }

bool pushQ(const Item&);

bool popQ(Item&);

};

#endif //_DESCRIPTION_H_

//define.cpp

/**

*Copyright U+00A9 2018 XXXXX. All Right Reserved.

*Filename:

*Author:XXXXXX

*Date:2018.12.01

*Version:VS 2013

*Description:

**/

#include

//#include

#include"description.h"

using namespace std;

void Customer::set(long t)

{

processtime = rand() % 3 + 1;//随机生成1~3之间的数,代表每个顾客的处理时间

begin_time = t;

}

Queue::Queue(int Size):Max_num(Size)//对于数据成员为引用&或者非静态const的必须利用初始化列表

{

front = rear = nullptr;

num = 0;

}

Queue::~Queue()//将剩余队列中的数据删除,释放内存空间

{

Node *temp;

while (front != nullptr)

{

temp = front;

front = front->next;

delete temp;

}

cout << "The rest object is erased!" << endl;

}

bool Queue::pushQ(const Item &item)

{

if (isfull()) return false;

Node *temp = new Node;

temp->item = item;

temp->next = nullptr;

if (front == nullptr)

front = temp;

else

rear->next = temp;

rear = temp;

++num;

return true;

}

bool Queue::popQ(Item &item)

{

if (isempty()) return false;

Node *temp;

temp = front;

item = front->item;

front = front->next;

delete temp;

--num;

if (num == 0) rear = nullptr;

return true;

}

//main.cpp

/**

*Copyright U+00A9 2018 XXXXXX. All Right Reserved.

*Filename:

*Author:XXXXXXX

*Date:2018.12.01

*Version:VS 2013

*Description:

**/

#include

#include

#include"windows.h"

#include"description.h"

#include

using namespace std;

bool newcustomer(double);

int main()

{

srand(time(0));

cout << "Enter maximum size of queue: ";

int qs;

cin >> qs;

Queue line(qs);

cout << "Enter the number of simulation hours: ";

int hours;

cin >> hours;

long cyclelimit = 60 * hours;

cout << "Enter the average number of customers per hour: ";

double perhour;

cin >> perhour;

double min_per_cus = 60.0 / perhour;//计算多少分钟来一个办理者

Item temp;

long turnaway = 0;

long customers = 0;

long served = 0;

long sum_line = 0;

int wait_time = 0;

long line_wait = 0;

for (int cycle = 0; cycle < cyclelimit; cycle++)//将总共时间分成若干个1分钟

{

if (newcustomer(min_per_cus))

{

if (line.isfull())

turnaway++;//如果队列满了,此时新顾客将会离去

else

{

customers++;

temp.set(cycle);//将第cycle分钟设置为顾客的初始时间

line.pushQ(temp);

}

}

if (wait_time <= 0 && !line.isempty())//如果队列不为空并且前一个顾客已经办理好wait_time<=0

{

line.popQ(temp);//出队列

wait_time = temp.get_pt();//重新设置新顾客的办理时间

line_wait += cycle - temp.get_bt();//整个队列等待一个人办好业务所经历的时间

++served;//已经办理好的人数加1

}

if (wait_time > 0)

--wait_time;//按每分钟为单位等前一个顾客办理好

sum_line += line.get_num();//所有时刻队列的长度总和

}

if (customers > 0)

{

cout << "customers accepted: " << customers << endl;

cout << "customers served: " << served << endl;

cout << "turnaways: " << turnaway << endl;

cout << "average queue size: ";

cout.precision(2);

cout.setf(ios_base::fixed, ios_base::floatfield);

cout << double(sum_line / cyclelimit) << endl;

cout << "average wait time: "

<< double(line_wait / served) << "minutes";

}

else

cout << "no customers!";

cout << "Done!";

system("pause");

return 0;

}

bool newcustomer(double x)//通过此函数来模拟每分钟是否来新顾客

{

return rand()*x / RAND_MAX < 1;

}

Note:对于数据成员为引用或者是非静态const类型,都必须对于构造函数采用初始化列表形式去赋值

程序运行结果如下图

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