C#，数值计算——Midinf的计算方法与源程序

1 文本格式

using System;

namespace Legalsoft.Truffer
{
    public class Midinf : Midpnt
    {
        public new double func(double x)
        {
            return funk.funk(1.0 / x) / (x * x);
        }

        public Midinf(UniVarRealValueFun funcc, double aa, double bb) : base(funcc, aa, bb)
        {
            base.a = 1.0 / bb;
            base.b = 1.0 / aa;
        }
    }
}
 

2 代码格式

using System;

namespace Legalsoft.Truffer
{
    public class Midinf : Midpnt
    {
        public new double func(double x)
        {
            return funk.funk(1.0 / x) / (x * x);
        }

        public Midinf(UniVarRealValueFun funcc, double aa, double bb) : base(funcc, aa, bb)
        {
            base.a = 1.0 / bb;
            base.b = 1.0 / aa;
        }
    }
}