代码随想录算法训练营第58天|583. 两个字符串的删除操作、72. 编辑距离

583. 两个字符串的删除操作

https://leetcode.cn/problems/delete-operation-for-two-strings/

class Solution {
public:
    int minDistance(string word1, string word2) {
        vector> dp (word1.size() + 1, vector(word2.size() + 1, 0));
        for (int i = 1; i <= word1.size(); i++) dp[i][0] = i;
        for (int j = 1; j <= word2.size(); j++) dp[0][j] = j;
        for (int i = 1; i <= word1.size(); i++) {
            for (int j = 1; j <= word2.size(); j++) {
                if (word1[i - 1] == word2[j - 1]) {
                    dp[i][j] = min(dp[i - 1][j - 1], min(dp[i - 1][j], dp[i][j - 1]) + 1);
                }
                else dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + 1;
            }
        }
        return dp.back().back();
    }
};

72. 编辑距离

https://leetcode.cn/problems/edit-distance/

class Solution {
public:
    int minDistance(string word1, string word2) {
        vector> dp(word1.length() + 1, vector(word2.length() +1, 0));
        for (int i = 1; i <= word1.length(); i++) dp[i][0] = i;
        for (int j = 1; j <= word2.length(); j++) dp[0][j] = j;
        for (int i = 1; i <= word1.length(); i++) {
            for (int j = 1; j <= word2.length(); j++) {
                if (word1[i - 1] == word2[j - 1]) {
                    dp[i][j] = dp[i - 1][j - 1];
                }
                else {
                    dp[i][j] = min(dp[i - 1][j - 1], min(dp[i - 1][j], dp[i][j - 1])) + 1;
                }
            }
        }
        return dp.back().back();
    }
};