12.数值的整数次方

给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方

public class Solution {
    public double Power(double base, int exponent) {
        double result = 1.0;
        for(int n = exponent; n != 0; n /= 2) {
            if(n % 2 != 0) {
                result *= base;
            }
            base *= base;
        }
        return exponent > 0? result:1/result;
  }
}

你可能感兴趣的:(12.数值的整数次方)