字符串查找--B中是否有元素不在A中

#include <stdio.h>

int main(int argc, char const *argv[])

{

	char str[26]="AFDKJASD";

	char str2[26]="AAAAZ";

	find_not_include_string(str,str2);

	return 0;

}



void find_not_include_string(char *str,char *sub_str)

{



	int  father_str[26]={0};

	int   sub_str[26]={0};



	if (*str==NULL||*sub_str==NULL)

	{

		return;

	}



	for (int i = 0; i < strlen(str); ++i)

	{

		father_str[str[i]-'A']++;

	}

	for (int i = 0; i < strlen(sub_str); ++i)

	{

		sub_str[sub_str[i]-'A']++;

	}

	for (int i = 0; i < 26; ++i)

	{

		if(father_str[i]==0&&sub_str[i] != 0)

		{



			printf("%c is not in str!\n", i+'A');

			break;

		}

	}



	printf("%s\n","str2 is include by str!" );

}