【年少的风】求1000以内的‘完数’

完数：一个数如果恰好等于除其本身的因子之和

例：28=1+2+4+7+14

public class Test53 {

    public static void main(String[] args) {
        int sum, i, j;
        int count = 0;
        int[] a = new int[50];

        System.out.println("1000以内的完数有：");

        for(i = 2; i < 1000; i++){
            sum = 0;
            count = 0;
            for(j = 0; j < 20; j++){
                a[j] = 0;
            }
            for(j = 1; j <= i/2; j++) {
                if(i%j == 0){
                    sum += j;
                    a[count] = j;
                    count++;
                }
            }
            if(sum == i){
                System.out.print(i + " = ");
                for(j = 0; j < count; j++){
                    System.out.print(a[j] + " + ");
                }
                System.out.print("\b\b\b\n");
            }
        }
    }

}